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3 years ago

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A scientist is asking you what would happen to Radon-226 (represented by Ra on the graph and 226 is the atomic mass) if instead

of a purple arrow after Radon-226 there was a single green arrow. What would the result of this reaction on Radon be?

1 answer:

ladessa [460]3 years ago

6 0

The sky legit green today

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A 10kg block is Pulled along a horizontal

Leviafan [203]

Answer:

Explanation:

I hate these kinds of problems, luckily I can't understand how much the kinetic friction is for this , the words are all mixed around. and don't read well. Maybe this went through a translator program? My suggestion draw the free body diagram. so you can see where the forces are, and how they are acting. getting the free body diagram right.. usually makes these problems pretty straight forward. just do the steps and you get the answer.

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3 years ago

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If the mass of the products measured 120 g, what would be the mass of the reactants?

aksik [14]

According to law of conservation of mass, mass of reactant = mass of products

So answer is C

Hope it helps!

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3 years ago

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An object moving with a speed of 5m/s comes to rest in 10s after the brakes are applied . What is the initial velocity?

Flauer [41]

Initial velocity is 5m/s.

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2 years ago

A 60 year old person has a threshold of hearing of 95.0 dB for a sound with frequency f=10,000 Hz. By what factor must the inten

Nadusha1986 [10]

Answer:

The intensity increased by a factor of 158489

Explanation:

Given that,

Sound level = 95.0 dB

Sound level = 43.0 dB

Frequency = 10000 Hz

We need to calculate the ratio of sound intensity

Using formula of sound level

$sound\ level =10 log\dfrac{I}{I_{0}}$

Put the value into the formula

$95.0=10\ log\dfrac{I_{1}}{I_{0}}$ ...(I)

$43.0=10\ log\dfrac{I_{2}}{I_{0}}$ .....(II)

Subtracting these equations

$52.0=10\ log\dfrac{I_{1}}{I_{2}}$

$\log\dfrac{I_{1}}{I_{2}}=5.2$

Taking inverse log

$\dfrac{I_{1}}{I_{2}}=10^{5.2}$

$\dfrac{I_{1}}{I_{2}}=158489$

Hence, The intensity increased by a factor of 158489

4 0

3 years ago

Helium gas is compressed by an adiabatic compressor from an initial state of 14 psia and 50°F to a final temperature of 320°F in

iVinArrow [24]

Answer:

The value is $P_2 = 40.54 \ psla$

Explanation:

From the question we are told that

The initial pressure is $P_1 = 14\ psla$

The initial temperature is $T_1 = 50 \ F = (50 - 32) * [\frac{5}{9} ] + 273 = 283 \ K$

The final temperature is $T_2 = 320 \ F = (320 - 32) * [\frac{5}{9} ] + 273 =433 \ K$

Generally the equation for adiabatic process is mathematically represented as

$PT^{\frac{\gamma}{1- \gamma} } = Constant$

=> $P_1T_1^{\frac{\gamma}{1- \gamma} } = P_2T_2^{\frac{\gamma}{1- \gamma} }$

Generally for a monoatomic gas $\gamma = \frac{5}{3}$

So

$14 * 283^{\frac{\frac{5}{3} }{1- [\frac{5}{3} ]} } =P_2 * 433^{\frac{\frac{5}{3} }{1- [\frac{5}{3} ]} }$

=> $14 * 283^{-2.5} =P_2 * 433^{-2.5}$

=> $P_2 = 40.54 \ psla$

8 0

2 years ago