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3 years ago

Hi i can i have some help

Physics

1 answer:

Ymorist [56]3 years ago

4 0

Answer:

The temperature-time diagram is attached below

When ethanol is heating -120°C, its temperature rises till -114°C. Then the temperature remains constants at -114°C° till all of the ethanol is converted from Solid to Liquid. After that the temperature starts to rise again till 78°C. Then the temperature remains constants till all the liquid is converted into gas.

The slopes depends on rate of heating and specific heat capacity of ethanol.

The plateaus depend on rate of heating and latent heat of fusion and latent heat of vaporization.

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A billiard ball with a mass of 1.5kg is moving at 25m/s and strikes a second ball with a mass of 2.3 kg that is motionless. Find

aliya0001 [1]

Answer:

The velocity of the second ball after the collision will be 16.3 m/s.

Step-by-Step Explanation:

Law of conservation of momentum states that the total momentum of an isolated remains the same before and after the collision.

Let: mass of the first ball = m1 = 1.5 kg

mass of the second ball = m2 = 2.3 kg

Momentum before the collision:

velocity of the first ball = v1 = 25 m/s

velocity of the second ball = v2 = 0 m/s

[tex] Initial momentum = m1v1 + m2v2 = 1.5*25 + 2.3*0 = 37.5 kgm/s [\tex]

Momentum after the collision:

velocity of the first ball = v1 = 0 m/s

velocity of the second ball = v2 = x

[tex]momentum after the collision= m1v1 + m2v2 = 1.5*0 + 2.3*x = 2.3*x[\tex]

According to law of conservation of momentum:

Initial momentum = Momentum after collision

37.5 = 2.3*x

⇒ x = 37.5/2.3

x = 16.3 m/s

4 0

3 years ago

It is known that the gravitational force of attraction between two alpha particles is much weaker than the electrical repulsion.

natali 33 [55]

Answer:

The ratio of gravitational force to electrical force is 3.19 x 10^-36

Explanation:

mass of an alpha particle = 6.64 x $10^{-27}$ kg

charge on an alpha particle = +2e = +2(1.6 x $10^{-19}$ C) = 3.2 x $10^{-19}$ C

distance between particles = d

For gravitational attraction:

The force of gravitational attraction F = $\frac{Gm^{2} }{r^{2} }$

where G = gravitational constant = 6.67 x $10^{-11}$ m^3 kg^-1 s^-2

r = the distance between the particles = d

m = the mass of each particle

therefore, gravitational force = $\frac{6.67*10^{-11}*(6.64*10^{-27} )^{2} }{d^{2} }$ = $\frac{2.94*10^{-63} }{d^{2} }$ Newton

For electrical repulsion:

Electrical force between the particles = $\frac{-kQ^{2} }{r^{2} }$

where k is the Coulomb's constant = 9.0 x $10^{9}$ N•m^2/C^2

r = distance between the particles = d

Q = charge on each particle

therefore, electrical force = $\frac{-9*10^{9}*(3.2*10^{-19} )^{2} }{d^{2} }$ = $\frac{-9.216*10^{-28} }{d^{2} }$ Newton

the negative sign implies that there is a repulsion on the particles due to their like charges.

Ratio of the magnitude of gravitation to electrical force = $\frac{2.94*10^{-63} }{9.216*10^{-28} }$

==> 3.19 x 10^-36

8 0

3 years ago

A has the magnitude 14.4 m and is angled 51.6° counterclockwise from the positive direction of the x axis of an xy coordinate sy

Ad libitum [116K]

Answer:

Ã in unit vector notation = 12.26485i + 7.54539j

B in unit vector notation = 16.3516i + 3.11529j

Explanation:

The detailed steps and calculation is shown in the attachment.

7 0

3 years ago

Charlie Brown kicks a football at 20.5 m/s at 31.0°. It lands on flat ground 2.15 s later. How far away did it land? (Unit = m)

yarga [219]

Answer:

distance, x = 38.17 m

Given:

velocity of the football, v = 20.5 m/s

football projected at an angle, $\theta = 30^{\circ}$

Period of flight, T = 2.15 s

Solution:

Since, the velocity is projected at some angle, so it can be resolved in horizontal and vertical components:

vertical component, $u_{v} = usin\theta$

horizontal component, $u_{h} = ucos\theta$

the component responsible to cover certain distance is $u_{h} = ucos\theta$

Therefore, the distance covered by the football, x is given by:

$x = ucos\theta \times T$

⇒ $x = 20.5cos30^{\circ}\times 2.15$

x = 38.17 m

7 0

3 years ago

What is a example of nuclear fusion

andrew11 [14]

Energy of our sun. It composed of a lot of hydrogen and by the two fusion of isotopes. Helium is then released.

4 0

4 years ago