Question

6. A 1,780kg car moving at 14m/s takes a turn around a circle with a radius of 50.0m.

Answer 1

1) Centripetal acceleration: $3.9 m/s^2$

2) Centripetal force: 6942 N

Explanation:

1)

For an object moving in uniform circular motion (=circular motion with constant  speed), the net acceleration is the centripetal acceleration, directed towards the centre of the trajectory and whose magnitude is given by

$a=\frac{v^2}{r}$

where

v is the speed

r is the radius of the circle

For the car in this problem, we have

v = 14 m/s is the speed

r = 50.0 m is the radius

Substituting, we find the acceleration:

$a=\frac{14^2}{50.0}=3.9 m/s^2$

2)

The net force acting upon the car is the centripetal force, also acting towards the centre of the circular path, and whose magnitude is given by

$F=ma$

where

m is the mass

a is the centripetal acceleration

For the car in this problem, we have:

m = 1780 kg is the mass

$a=3.9 m/s^2$ is the acceleration

Substituting, we find the centripetal force:

$F=(1780)(3.9)=6942 N$

Learn more about centripetal acceleration and force:

brainly.com/question/2562955

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