2 years ago

At what distance from a 0.100 C charge will the electric field be 10000 N/C? (Unit = m)

Physics

1 answer:

krok68 [10]2 years ago

7 0

Answer:

Explanation:

$F = k \frac{Q}{r^{2}} \\10000 = 8.99 * 10^{9} * \frac{0.1}{r^{2}} => r^{2} = 8.99 * 10^{5} * 0.1 = 89900 => r = 299.83 m = 300 m$

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