The dicotyledons, also known as dicots, are one of the two groups into which all the flowering plants or angiosperms were formerly divided. The name refers to one of the typical characteristics of the group, namely that the seed has two embryonic leaves or cotyledons.
The pH scale for acids and bases ranges from 1 - 14. The answer is letter C. The rest of the choices do not answered the question above. There are quite a few relationships between [H+] and [OH−] ions. And because there is a large range of number between 10 to 10-15 M, the pH is used. pH = -log[H+] and pOH = -log[OH−]. In aqueous solutions, [H+ ][OH- ] = 10-14. From here we can derive the values of each concentration.
-log[H+ ] + -log[OH- ] = -log[10-14]
pH + pOH = 14
So pH = 14 – pOH and pOH = 14 –
pH
It would be B.
Answer:
- The first equation, <em>a. PV = nRT</em>, <u>is not</u> <em>a valid statement of the ideal gas law.</em>
Explanation:
The basic expression for the<em> ideal gas law</em> is:
.......... [Equation 1]
Where:
- n is the number of moles of the gas
- V is the volume occupied by the gas
- p is the pressure exerted by the gas molecules
- T is the temperature in absolute scale (Kelvin)
- R is the Universal gas constant (0.0821 atm-liter /K-mol or the equivalents in other units)
You can perform different algebraic operations to obtain equivalent equations:
<u>Choice b) Divide equation 1 by T and you get</u>:
- pV / T = nR, which is the choice b. from your list.
<u>Choice c) Divide equation 1 by n × V and you get</u>:
- p/n = RT / V, which is the choice c. from your list.
<u>Choice d) Divide equation 1 n × T and you get</u>:
- pV / (nT) = R, which is the choice d. from your list.
The choice a. p = nRTV states that p and V are in direct relation, when the ideal gas law states that p and V are inversely related, so that equation is wrong.
<u>Conclusion: </u>the choice a, p = nRTV, is not a statement of the ideal gas law.
Answer:
d
Explanation:
the rainwater is not infiltrating into the ground.
Answer:
True
Explanation:
Water boils at 373 kelvins. ... Absolute zero is –273.15° C or –459.67° F. The "size" of a one degree change in temperature is exactly the same in the Celsius and Kelvin scales, so the freezing point of water is at a temperature of 273.15 kelvins (that is, 273.15 degrees above absolute zero