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olga_2 [115]
3 years ago
9

Is solubility a physical change? Defend your answer.

Chemistry
2 answers:
expeople1 [14]3 years ago
6 0
Yes it is a physical change
fredd [130]3 years ago
3 0

Answer:

yes

Explanation:

Solubility is an observation and no chemical reaction takes place. The composition of the compound/element is not changed.

- Hope that helped! Please let me know if you need further explanation.

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From the value Kf=1.2×109 for Ni(NH3)62+, calculate the concentration of NH3 required to just dissolve 0.016 mol of NiC2O4 (Ksp
Nina [5.8K]

<u>Answer:</u> The concentration of NH_3 required will be 0.285 M.

<u>Explanation:</u>

To calculate the molarity of NiC_2O_4, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Moles of NiC_2O_4 = 0.016 moles

Volume of solution = 1 L

Putting values in above equation, we get:

\text{Molarity of }NiC_2O_4=\frac{0.016mol}{1L}=0.016M

For the given chemical equations:

NiC_2O_4(s)\rightleftharpoons Ni^{2+}(aq.)+C_2O_4^{2-}(aq.);K_{sp}=4.0\times 10^{-10}

Ni^{2+}(aq.)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K_f=1.2\times 10^9

Net equation: NiC_2O_4(s)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K=?

To calculate the equilibrium constant, K for above equation, we get:

K=K_{sp}\times K_f\\K=(4.0\times 10^{-10})\times (1.2\times 10^9)=0.48

The expression for equilibrium constant of above equation is:

K=\frac{[C_2O_4^{2-}][[Ni(NH_3)_6]^{2+}]}{[NiC_2O_4][NH_3]^6}

As, NiC_2O_4 is a solid, so its activity is taken as 1 and so for C_2O_4^{2-}

We are given:

[[Ni(NH_3)_6]^{2+}]=0.016M

Putting values in above equations, we get:

0.48=\frac{0.016}{[NH_3]^6}}

[NH_3]=0.285M

Hence, the concentration of NH_3 required will be 0.285 M.

7 0
3 years ago
I need help with this question...<br>​
ivanzaharov [21]
I’m guessing the answer is AX (the first one) sorry if I am wrong tho
5 0
2 years ago
Read 2 more answers
What is the value of the activation energy of the uncatalyzed reaction?
Lubov Fominskaja [6]
The value of the activation energy of an uncatalyzed reaction is greater than that of a catalyzed reaction. As we know, a catalyst provides an alternative path for the reaction to happen at a faster rate. So, for a catalyzed reactio, activation energy is lesser than the original path.
6 0
3 years ago
2. What is the volume of 40.0 g of N2 at STP?
vampirchik [111]

Answer:

Molar mass of

N

2

=

28 g/mol

Moles of

40.5 g N

2

gas

=

40.5 g

28 g/mol

=

1.45 mol

1 mol

of any gas at

STP

occupies

22.4 L

of volume.

1.45 mol

of

N

2

gas will occupy

1.45

mol

×

22.4 L

1

mol

=

32.48 L

3 0
2 years ago
The reaction shown below occurs in the blood between hemoglobin (Hb) and oxygen.
OlgaM077 [116]

Answer:

A, B, C

Explanation:

Notice that this reaction involves double arrows, meaning this represents an equilibrium reaction in which we observe a forward reaction (combination of hemoglobin and oxygen) and a reverse reaction (decomposition of the oxyhemoglobin complex).

Upon inhalation of oxygen, it accesses the blood of a person and binds to hemoglobin, so the following reaction proceeds to the right.

Similarly, the opposite process takes place in muscles, oxyhemoglobin is decomposed back into hemoglobin and oxygen.

The equilibrium constant reaction is relatively high, since at standard conditions, this is a spontaneous reaction, hemoglobin combines with oxygen without any additional external source of energy.

7 0
3 years ago
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