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joja [24]
2 years ago
8

Nitrobenzene contains 5 hydrogen atoms, 6 carbon atoms, 2 oxygen atoms, and 1 nitrogen atom. what is the chemical formula for ni

trobenzene?

Chemistry
2 answers:
ollegr [7]2 years ago
7 0

C₆H₅NO₂

<h3>Further explanation</h3>

Nitrobenzene contains:

  • 5 hydrogen atoms,
  • 6 carbon atoms,
  • 2 oxygen atoms, and
  • 1 nitrogen atom.

The chemical formula for nitrobenzene is C₆H₅NO₂.

Nitrobenzene is one of benzene derivatives, precisely including the type of monosubstituted benzenes.

The molecular structure of phenyl  \boxed{ \ C_6H_5- \ } is formed by removing one H atom from the benzene \boxed{ \ C_6H_6 \ } molecule. A substituent is bound to the C atom which loses the H atom so it is called monosubstituted benzene.

In the naming of monosubstituted benzenes, benzene is the parent name and the substituent is indicated by a prefix.

  • nitro is the substituent
  • benzene is the parent name

When benzene is reacted with a mixture of concentrated nitric acid and concentrated sulfuric acid, it yields nitrobenzene.

\boxed{ \ C_6H_6 + HNO_2 \ (with \ H_2SO_4 \ in \ 30^0C-40^0C) \rightarrow C_6H_5NO_2 + H_2O}

- - - - - - -

<u>Notes:</u>

  • Benzene and compounds having similar chemical properties to benzene are called aromatic compounds.
  • Benzene is a colorless, poisonous liquid with a specific odor. it dissolves in organic solvents in organic solvents such as alcohol, ether, and acetic acid. Benzene is also good for non-polar substances.
  • Nitrobenzene is used in the manufacture of aniline and other organic chemicals. Nitrobenzene is a pale yellow, oily, and highly toxic liquid with the odor of bitter almonds.
<h3>Learn more</h3>
  1. Calculating the pH value of weak base brainly.com/question/9040743
  2. About the solution as a homogeneous mixture  brainly.com/question/637791
  3. About the mass and density of substances  brainly.com/question/4053884

Keywords: nitrobenzene, contains, 5 hydrogen atoms, 6 carbon, 2 oxygen, and 1 nitrogen. the chemical formula, benzene, monosaturated, phenyl, aromatic compounds

Maru [420]2 years ago
4 0

The chemical formula of nitrobenzene is C6H5NO2.

From this formula, we can see that a molecule of nitrobenzene is made up of 6 carbon atoms, 5 hydrogen atoms, 1 nitrogen atom and 2 oxygen atoms. Nitrobenze is an organic, aromatic, nitro compound which is insoluble in water. It has pale yellow colour but the colour turns to greenish yellow when the liquid is freezed. Nitrobenze is manufacture by the nitration of benzene with mixture of H2SO4 and HNO3. Nitrobenze can be used to mask unpleasant odors and also has perfume for soaps.

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Answer:

Because it wouldn't make any sense

Explanation:

First of all, I think it's important to highlight the definition of isotope.

Isotope (Wikipedia): Variants of a particular chemical element <u>which differ in neutron number</u>...

This means that two isotopes are the same element but have different net mass per atom, due to the different number of neutrons.

Therefore, it's important to make the definition on the same isotope so that the proportion is equal. If the definition would be made on different isotopes, the proportion wouldn't have any sense. Let me be clear with this example:

mass in grams of a C-12 atom = 1.9944235 × 10 ^ -23 g  --> this is the mass of a single C atom.

By definition --> 1 mol of anything = 6.02 x 10 ^ 23 particles of anything

Therefore, we know how much a single C atom weights. How many grams do you think that 6.02 x 10 ^ 23 atoms of C (i.e a mol of C) could weight??

1 single C atom ----------------------------- 1.9944235 × 10 ^ -23 g

6.02 x 10 ^ 23 atoms of C   ------------ <u>12.006 g  !!</u>

These 12 g is the same quantity than above! Therefore, 1 mol of C weights 12 g. If the definition were made with 13 g of C-13 (the other C isotope), these numbers will not be the same --> There would be a contradiction.

Regarding the second question, we need to search Ne-20 atomic mass in grams -->  3,3509177 × 10 ^ -23 g

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Sergeeva-Olga [200]

Explanation:

The given data is as follows.

 Weight of solute = 75.8 g,   Molecular weight of solute (toulene) = 92.13 g/mol,    volume = 200 ml

  • Therefore, molarity of toulene is calculated as follows.

      Molarity = \frac{\text{weight of solute}}{\text{molecular weight of solute}} \times \frac{1000}{\text{volume of solution in ml}}

                    = \frac{75.8 g}{92.13 g/mol} \times \frac{1000}{200 ml}

                    = 4.11 M

Hence, molarity of toulene is 4.11 M.

  • As molality is the number of moles of solute present in kg of solvent.

So, we will calculate the molality of toulene as follows.

   Molality = \frac{\text{given weight of solute}}{\text{given molecular weight of solute}} \times \frac{1000}{\text{weight of solvent in grams}}

             = \frac{75.8 g}{92.13 g/mol} \times \frac{1000}{95.6 g}

             = 8.6 m

Hence, molality of given toulene solution is 8.6 m.

  • Now, calculate the number of moles of toulene as follows.

       No. of moles = \frac{mass}{\text{molar mass}}

                             = \frac{75.8 g}{92.13 g/mol}

                             = 0.8227 mol

Now, no. of moles of benzene will be as follows.

     No. of moles = \frac{mass}{\text{molar mass}}

                             = \frac{95.6 g}{78.11 g/mol}

                             = 1.2239 mol

Hence, the mole fraction of toulene is as follows.

         Mole fraction = \frac{\text{moles of toulene}}{\text{total moles}}

                             = \frac{0.8227 mol}{(0.8227 + 1.2239) mol}

                             = 0.402

Hence, mole fraction of toulene is 0.402.

  • As density of given solution is 0.857 g/cm^{3} so, we will calculate the mass of solution as follows.

         Density = \frac{mass}{volume}

     0.857 g/cm^{3} = \frac{mass}{200 ml}      (As 1 cm^{3} = 1 g)

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Therefore, calculate the mass percent of toulene as follows.

      Mass % = \frac{\text{mass of solute}}{\text{mass of solution}} \times 100

                   = \frac{75.8 g}{171.4 g} \times 100

                   = 44.22%

Therefore, mass percent of toulene is 44.22%.

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