Answer:
5.158 × 10²³ atoms K
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
Explanation:
<u>Step 1: Define</u>
33.49 g K
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of K - 39.10 g/mol
<u>Step 3: Convert</u>
<u />
= 5.15797 × 10²³ atoms K
<u>Step 4: Check</u>
<em>We are given 4 sig figs. Follow sig figs and round.</em>
5.15797 × 10²³ atoms K ≈ 5.158 × 10²³ atoms K
The equilibrium expression shows the ratio
between products and reactants. This expression is equal to the concentration
of the products raised to its coefficient divided by the concentration of the
reactants raised to its coefficient. The correct equilibrium expression for the
given reaction is:<span>
<span>H2CO3(aq) + H2O(l)
= H3O+(aq) + HCO3-1(aq)
Kc = [HCO3-1] [H3O+] / [H2O] [H2CO3]</span></span>
Answer:
J.J. Thomson’s experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons. Thomson proposed the plum pudding model of the atom, which had negatively-charged electrons embedded within a positively-charged “soup.”
Answer:
k ≈ 9,56x10³ s⁻¹
Explanation:
It is possible to solve this question using Arrhenius formula:
![ln\frac{k2}{k1} = \frac{-Ea}{R} (\frac{1}{T2} -\frac{1}{T1} )](https://tex.z-dn.net/?f=ln%5Cfrac%7Bk2%7D%7Bk1%7D%20%3D%20%5Cfrac%7B-Ea%7D%7BR%7D%20%28%5Cfrac%7B1%7D%7BT2%7D%20-%5Cfrac%7B1%7D%7BT1%7D%20%29)
Where:
k1: 1,35x10² s⁻¹
T1: 25,0°C + 273,15 = 298,15K
Ea = 55,5 kJ/mol
R = 8,314472x10⁻³ kJ/molK
k2 : ???
T2: 95,0°C+ 273,15K = 368,15K
Solving:
![ln\frac{k2}{k1} = 4,257](https://tex.z-dn.net/?f=ln%5Cfrac%7Bk2%7D%7Bk1%7D%20%3D%204%2C257)
![\frac{k2}{k1} = 70,593](https://tex.z-dn.net/?f=%5Cfrac%7Bk2%7D%7Bk1%7D%20%3D%2070%2C593)
![{k2} = 9,53x10^3 s^{-1}](https://tex.z-dn.net/?f=%7Bk2%7D%20%3D%209%2C53x10%5E3%20s%5E%7B-1%7D)
<em>k ≈ 9,56x10³ s⁻¹</em>
I hope it helps!
The number of protons is the atomic number