Answer:
#include <iostream>
using namespace std;
int main()
{
int inputNumber ;
cout << "Enter an interstate highway number:";
cin >> inputNumber ;
if(inputNumber<=0 || inputNumber >= 1000)
cout << inputNumber << " is not a valid interstate highway number" << endl ;
else{
if(inputNumber > 99){
cout << "I-"<<inputNumber<< " is auxiliary, ";
int temp = inputNumber % 100 ;
cout <<"serving I-"<<temp<<", ";
if(temp%2==0){
cout << "going east/west." << endl;
}
else{
cout << "going north/south." << endl;
}
}
else{
cout << "I-"<<inputNumber<< " is primary, ";
if(inputNumber%2==0){
cout << "going east/west." << endl;
}
else{
cout << "going north/south." << endl;
}
}
}
return 0;
}
Explanation:
- Check if input number is greater than 99, then display that the input number is auxiliary.
-
Check if remainder of input number/2 is equal to 0, then display that going east/west.
Answer: c) they have low genetic variability among them.
When a plant is grown for several generations of offspring of a plant, then there are some common things which are to be noted which are found similar in the offspring and in the parent of the offspring. The flowers and fruits and the time or season they come in are absolutely the same.
Answer: 133.88 MPa approximately 134 MPa
Explanation:
Given
Plane strains fracture toughness, k = 26 MPa
Stress at which fracture occurs, σ = 112 MPa
Maximum internal crack length, l = 8.6 mm = 8.6*10^-3 m
Critical internal crack length, l' = 6 mm = 6*10^-3 m
We know that
σ = K/(Y.√πa), where
112 MPa = 26 MPa / Y.√[3.142 * 8.6*10^-3)/2]
112 MPa = 26 MPa / Y.√(3.142 * 0.043)
112 = 26 / Y.√1.35*10^-2
112 = 26 / Y * 0.116
Y = 26 / 112 * 0.116
Y = 26 / 13
Y = 2
σ = K/(Y.√πa), using l'instead of l and, using Y as 2
σ = 26 / 2 * [√3.142 * (6*10^-3/2)]
σ = 26 / 2 * √(3.142 *3*10^-3)
σ = 26 / 2 * √0.009426
σ = 26 / 2 * 0.0971
σ = 26 / 0.1942
σ = 133.88 MPa
Yes that’s correct . It’s safer cause of the current are even
