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3 years ago

What ic engine for mechanic

1 answer:

4 0

Answer: There are two kinds of internal combustion engines currently in production: the spark ignition gasoline engine and the compression ignition diesel engine. Most of these are four-stroke cycle engines, meaning four piston strokes are needed to complete a cycle.

Explanation:

You might be interested in

How are isometric drawings and orthographic drawings similar?

sashaice [31]

Answer:

The horizontal lines of the orthographic drawing

are NOT horizontal in the isometric drawing but are projected at 30-degree and 60. ... degree angles, and the length of the lines remain the same in the isometric as they were in the orthographic.

Hope it's helpful to you

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5 0

4 years ago

Match the benefit of full synthetic oil with engine conditions: All engines

mart [117]

Answer:

1. All engines exhibit wear over time ⇒ Synthetic Improves engine protection by resisting oil breakdown.

Synthetic oil does not breakdown so easily which means that it protects the engine more and protects it from wearing.

2. Engines are cold at start-up and not while running ⇒ Synthetic provides maximum protection in extreme hot and cold temperature conditions.

By providing protection for the engine during cold and hot conditions, the engine will not be too cold when the car is started up.

3. If oil is thicker, engines lose power and efficiency ⇒ Synthetic has greater resistance to oil thickening to maintain engine efficiency.

Part of the characteristics of synthetic oil is that it does not get as thick as regular oil which means that the adverse effects of thick oil are spared on the engine.

7 0

3 years ago

Base course aggregate has a target density of 121.8 lb/ft3 in place It will be laid down and compacted in a rectangular street r

irakobra [83]

Answer:

total weight of the aggregate = 3594878.28 lbs

Explanation:

given data

density = 121.8 lb/ft³

area = 1000 ft x 60 ft x 6 in = 1000 ft x 60 ft x 0.5 ft

moisture = 3.5 %

compaction = 95%

solution

we get here first volume of the space that is filled with the aggregate that is

volume = 1000 ft x 60 ft x 0.5 ft = 30,000 cu ft

now we get fill space with aggregate that compact to 95% of dry density.

so we fill space with aggregate of density that is = 95% of 121.8

= 115.71 lb/ cu ft

so now dry weight of aggregate is

dry weight of aggregate = 30,000 × 115.71 = 3471300 lb

when we assume that moisture percentage is by weight

then weight of the moisture in aggregate will be

weight of the moisture in aggregate = 3.56 % of 3471300 lb

weight of the moisture in aggregate = 123578.28 lbs

and

we get total weight of the aggregate to fill space that is

total weight of the aggregate = 3471300 lb +123578.28 lb

total weight of the aggregate = 3594878.28 lbs

4 0

3 years ago

"Transportation is the way of expanding business activies" justify this statement with long answer

Leokris [45]

Answer:

Transportation methods ensure deliveries to and from your facility flow smoothly and arrive at their designated destinations on time. Because of the importance of transportation to your business's success, it's vital to include this factor in your supply chain management strategy.

So,transportation is the way of expanding business activities.

4 0

3 years ago

Shear plane angle and shear strain: In an orthogonal cutting operation, the tool has a rake angle = 16°. The chip thickness befo

Oduvanchick [21]

Answer:

shear plane angle Ф = 26.28°

shear strain 2.20

Explanation:

given data

angle = 16°

chip thickness t1 = 0.32 mm

cut yields chip thickness t2 = 0.72 mm

solution

we get here first chip thickness ratio that is

chip thickness ratio = $\frac{t1}{t2}$ ................. 1

put here value

chip thickness ratio = $\frac{0.32}{0.72}$

chip thickness ratio r = 0.45

so here shear angle will be Ф

tan Ф = $\frac{r*cos\alpha }{1-rsin\alpha}$ ............2

tan Ф = $\frac{0.45*cos16 }{1-rsin16}$

tan Ф = 0.4938

Ф = 26.28°

and

now we get shear strain that is

shear strain r = cot Ф + tan (Ф - α ) ................3

shear strain r = cot(26.28) + tan (26.28 - 16 )

shear strain r = 2.20

6 0

3 years ago