B - electric currents
Look into Lorentz force law if it would be helpful
If you look at the picture you will see how, but the answer is 0.5 Hz.
Answer:
A. 46.15 ohms
B. 1248 W
C. 2.25×10⁶ J
Explanation:
A. Determination of the resistance.
Current (I) = 5.2 A
Voltage (V) = 240 V
Resistance (R) =?
From ohm's law,
V = IR
240 = 5.2 × R
Divide both side by 5.2
R = 240 / 5.2
R = 46.15 ohms
B. Determination of the power.
Current (I) = 5.2 A
Voltage (V) = 240 V
Power (P) =?
P = IV
P = 240 × 5.2
P = 1248 W
C. Determination of the energy.
Power (P) = 1248 W
Time (t) = 30 minutes
Energy (E) =?
Next, we shall convert 30 minutes to seconds. This can be obtained as follow:
1 min = 60 s
Therefore,
30 min = 30 min × 60 s / 1 min
30 min = 1800 s
Finally, we shall determine the energy. This can be obtained as illustrated below:
Power (P) = 1248 W
Time (t) = 1800 s
Energy (E) =?
E = Pt
E = 1248 × 1800
E = 2.25×10⁶ J
Answer:
5069.04 seconds
Explanation:
The parameter we are looking for is called the Orbital period of the Hubble Space Telescope.
It is given as:
where r = radius of orbit of Hubble Space Telescope
G = gravitational constant =
M = Mass of earth
We are given that:
r = radius of the earth + distance of HST from earth
r =
M =
Therefore, T will be:
The orbital period of the Hubble Space Telescope is 5069.04 seconds.
147.09975 newton meters per second