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JulijaS [17]
3 years ago
12

How can you calculate distance when given power, time, and mass?

Physics
1 answer:
SVEN [57.7K]3 years ago
3 0

First step:         Power = (work done) / (time to do the work).

                 3490 watts = (work done) / (3 seconds)

     3490 joules/second = (work done) / (3 seconds)

Multiply each side by 3 seconds:

     Work done = (3490 x 3) joules  =  10,470 joules 


Second step:       Weight = (mass) x (gravity)

                 Weight of the crate = (425 kg) x (9.8 m/s²)

                                              =  4165 newtons


Step 3:     Work done  =  (force) x (distance)

                                 =  (weight) x (distance lifted)

            10,470 joules  =  (4165 newtons) x (distance)

Divide each side by 4165 newtons:

       Distance = 10,470 kg-m²/sec² / 4165 kg-m/s²

                     =        2.514... meters  (rounded)

You asked:  "How can you calculate ... ?"
Notice that I did the same thing in all 3 steps ... write down the formula
for finding a quantity, then write the numbers you know into the formula
to find the quantity. 

THAT's "how", and it all boils down to knowing the formulas and picking
the right one to work with.  The right one to pick is the one that talks about
all (or most) of the quantities that you know AND the quantity that you're
trying to find. 

For example, if you need to find how long it will take your turtle to walk
across the room, then you need a formula that talks about time, speed,
and distance.  You would not get much help from the formula that talks
about the pressure and volume of a gas, or one that talks about the
frequency and wavelength of light waves, or Einstein's formula  E=mc² 
for the equivalency of mass and energy.
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Dmitriy789 [7]

Answer:

In space there is no air resistance. on earth there is

in space there is no opposite forces acting on stopping the ball, so if you throw it it will go on forever.

on earth there is air resistance and gravity, this will pull the ball towards the ground and slow it down.

4 0
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Which planet has the most extreme temperature variations
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Answer:

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2 years ago
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A dinner plate falls vertically to the floor and breaks up into three pieces, which slide horizontally along the floor. Immediat
Olegator [25]

Answer:

Explanation:

There will be conservation of momentum along horizontal plane because no force acts along horizontal plane.

momentum of first piece = .320 kg x 2 m/s

= 0.64 kg m/s along x -axis.

momentum of second piece = .355 kg x 1.5 m/s

= 0.5325 kg m/s along y- axis .

Let the velocity of third piece be v and it is making angle of θ with x -axis .

Horizontal component of its velocity = .100 kg x v cosθ = .1 v cosθ

vertical  component of its velocity = .100 kg x v sinθ = .1 v sinθ

For making total momentum in the plane zero

.1 v cosθ = 0.64 kg m/s

.1 v sinθ = 0.5325 kg m/s

Dividing

Tanθ = .5325 / .64 = .83

θ = 40⁰.

The angle will be actually 180 + 40 = 220 ⁰ from positive x -axis.

6 0
2 years ago
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Help me please, need more assistance
Dmitrij [34]

Explanation:

12) q = mCΔT

125,600 J = (500 g) (4.184 J/g/K) (T − 22°C)

T = 82.0°C

13) Solving for ΔT:

ΔT = q / (mC)

a) ΔT = 1 kJ / (0.4 kg × 0.45 kJ/kg/K) = 5.56°C

b) ΔT = 2 kJ / (0.4 kg × 0.45 kJ/kg/K) = 11.1°C

c) ΔT = 2 kJ / (0.8 kg × 0.45 kJ/kg/K) = 5.56°C

d) ΔT = 1 kJ / (0.4 kg × 0.90 kJ/kg/K) = 2.78°C

e) ΔT = 2 kJ / (0.4 kg × 0.90 kJ/kg/K) = 5.56°C

f) ΔT = 2 kJ / (0.8 kg × 0.90 kJ/kg/K) = 2.78°C

14) q = mCΔT

q = (2000 mL × 1 g/mL) (4.184 J/g/K) (80°C − 20°C)

q = 502,000 J

20) q = mCΔT

q = (2000 g) (4.184 J/g/K) (100°C − 15°C) + (400 g) (0.9 J/g/K) (100°C − 15°C)

q = 742,000 J

24) q = mCΔT

q = (0.10 g) (0.14 J/g/K) (8.5°C − 15°C)

q = -0.091 J

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3 years ago
Study the force diagram to complete the sentences. The forces acting on the box are . The box will move to the .
Viktor [21]

Answer: unbalanced and right

Explanation:

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