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JulijaS [17]
3 years ago
12

How can you calculate distance when given power, time, and mass?

Physics
1 answer:
SVEN [57.7K]3 years ago
3 0

First step:         Power = (work done) / (time to do the work).

                 3490 watts = (work done) / (3 seconds)

     3490 joules/second = (work done) / (3 seconds)

Multiply each side by 3 seconds:

     Work done = (3490 x 3) joules  =  10,470 joules 


Second step:       Weight = (mass) x (gravity)

                 Weight of the crate = (425 kg) x (9.8 m/s²)

                                              =  4165 newtons


Step 3:     Work done  =  (force) x (distance)

                                 =  (weight) x (distance lifted)

            10,470 joules  =  (4165 newtons) x (distance)

Divide each side by 4165 newtons:

       Distance = 10,470 kg-m²/sec² / 4165 kg-m/s²

                     =        2.514... meters  (rounded)

You asked:  "How can you calculate ... ?"
Notice that I did the same thing in all 3 steps ... write down the formula
for finding a quantity, then write the numbers you know into the formula
to find the quantity. 

THAT's "how", and it all boils down to knowing the formulas and picking
the right one to work with.  The right one to pick is the one that talks about
all (or most) of the quantities that you know AND the quantity that you're
trying to find. 

For example, if you need to find how long it will take your turtle to walk
across the room, then you need a formula that talks about time, speed,
and distance.  You would not get much help from the formula that talks
about the pressure and volume of a gas, or one that talks about the
frequency and wavelength of light waves, or Einstein's formula  E=mc² 
for the equivalency of mass and energy.
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laila [671]

Answer:

The ball is dropped at a height of 9.71 m above the top of the window.

Explanation:

<u>Given:</u>

  • Height of the window=1.5 m
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Now using equation of motion in one dimension we have

s=ut+\dfrac{at^2}{2}

Let u be the velocity of the ball when it reaches the top of the window

then

1.5=0.15u+\dfrac{9.8\times0.15^2}{2}\\u=3.96\ \rm m/s\\

Now u is the final velocity of the ball with respect to the top of the building

so let t be the time taken for it to reach the top of the window with this velocity

3.96=gt\\t=0.4\ \rm s\\

Let h be the height above the top of the window

h=\dfrac{gt^2}{2}\\\\h=\dfrac{9.8\times 0.4^2}{2}\\h=9.71\ \rm m

3 0
3 years ago
a horse runs with an initial velocity of 11m/s and slows to 5.2 m/s over a time interval of 3.1 s what is the horse's average ac
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a = change in v / change in time

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Explanation:

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How many neutrons does element x have if it's atomic number is 27 and it's mass number is 74
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Atomic mass=Proton count+ neutron count

Neuton Count=Atomic mass-Proton count

Proton count=Atomic number=27

Mass number=74

Neuton count= 74-27=47

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What is the average velocity of the object?
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