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JulijaS [17]
3 years ago
12

How can you calculate distance when given power, time, and mass?

Physics
1 answer:
SVEN [57.7K]3 years ago
3 0

First step:         Power = (work done) / (time to do the work).

                 3490 watts = (work done) / (3 seconds)

     3490 joules/second = (work done) / (3 seconds)

Multiply each side by 3 seconds:

     Work done = (3490 x 3) joules  =  10,470 joules 


Second step:       Weight = (mass) x (gravity)

                 Weight of the crate = (425 kg) x (9.8 m/s²)

                                              =  4165 newtons


Step 3:     Work done  =  (force) x (distance)

                                 =  (weight) x (distance lifted)

            10,470 joules  =  (4165 newtons) x (distance)

Divide each side by 4165 newtons:

       Distance = 10,470 kg-m²/sec² / 4165 kg-m/s²

                     =        2.514... meters  (rounded)

You asked:  "How can you calculate ... ?"
Notice that I did the same thing in all 3 steps ... write down the formula
for finding a quantity, then write the numbers you know into the formula
to find the quantity. 

THAT's "how", and it all boils down to knowing the formulas and picking
the right one to work with.  The right one to pick is the one that talks about
all (or most) of the quantities that you know AND the quantity that you're
trying to find. 

For example, if you need to find how long it will take your turtle to walk
across the room, then you need a formula that talks about time, speed,
and distance.  You would not get much help from the formula that talks
about the pressure and volume of a gas, or one that talks about the
frequency and wavelength of light waves, or Einstein's formula  E=mc² 
for the equivalency of mass and energy.
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do constructive inference occur when the compression of one wave meets up with the compression of a second wave
Ugo [173]

Answer:

Yes

Explanation:

There are two types of interference possible when two waves meet at the same point:

- Constructive interference: this occurs when the two waves meet in phase, i.e. the crest (or the compression, in case of a longitudinale wave) meets with the crest (compression) of the other wave. In such a case, the amplitude of the resultant wave is twice that of the original wave.

- Destructive interferece: this occurs when the two waves meet in anti-phase, i.e. the crest (or the compression, in case of a longitudinal wave) meets with the trough (rarefaction) of the other wave. In this case, the amplitude of the resultant wave is zero, since the amplitudes of the two waves cancel out.

In this problem, we have a situation where the compression of one wave meets with the compression of the second wave, so we have constructive interference.

6 0
3 years ago
A block of 250-mm length and 54 × 40-mm cross section is to support a centric compressive load P. The material to be used is a b
musickatia [10]

Answer:

P = 17.28*10⁶ N

Explanation:

Given

L = 250 mm = 0.25 m

a = 0.54 m

b = 0.40 m

E = 95 GPa = 95*10⁹ Pa

σmax = 80 MPa = 80*10⁶ Pa

ΔL = 0.12%*L = 0.0012*0.25 m = 3*10⁻⁴ m

We get A as follows:

A = a*b = (0.54 m)*(0.40 m) = 0.216 m²

then, we apply the formula

ΔL = P*L/(A*E)  ⇒ P = ΔL*A*E/L

⇒  P = (3*10⁻⁴ m)*(0.216 m²)*(95*10⁹ Pa)/(0.25 m)

⇒  P = 24624000  N = 24.624*10⁶ N

Now we can use the equation

σ = P/A

⇒  σ = (24624000  N)/(0.216 m²) = 114000000 Pa = 114 MPa > 80 MPa

So σ > σmax  we use σmax

⇒  P = σmax*A = (80*10⁶ Pa)*(0.216 m²) = 17280000 N = 17.28*10⁶ N

7 0
3 years ago
A 2kg book is moved from a shelf that is 2m off the ground to a shelf that is 1.5m off the ground, what is it’s change in gravit
Ket [755]
The gravitational energy is going up subtracting the energy that was on the ground
3 0
4 years ago
If your car runs out of gas and you must push it 250 m to the nearest gas station. How much work is done on the car if it is pus
tankabanditka [31]

Answer:

1750 Joules.

Explanation:

Work done = force * distance

= 7 * 250

= 1750 Joules.

6 0
3 years ago
Ride and average of 15mph for 30 miles, how long does it take?
dalvyx [7]

Answer:

2 hrs

Explanation:

time = distance ÷ speed

3 0
3 years ago
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