Answer:
I'd say 8 h given the provided nformation
It’s c, all the other answers are far from the real answer
<u>Answers with step-by-step explanation:</u>
1. Area of sector 1 = ![\frac{90}{360} \times \pi \times 12^2 = 36\pi](https://tex.z-dn.net/?f=%5Cfrac%7B90%7D%7B360%7D%20%5Ctimes%20%5Cpi%20%5Ctimes%2012%5E2%20%3D%2036%5Cpi)
2. Area of sector 2 = ![\frac{45}{360} \times \pi \times 19^2 = \frac{2527}{8} \pi](https://tex.z-dn.net/?f=%5Cfrac%7B45%7D%7B360%7D%20%5Ctimes%20%5Cpi%20%5Ctimes%2019%5E2%20%3D%20%5Cfrac%7B2527%7D%7B8%7D%20%5Cpi)
3. Area of sector 3 = ![\frac{270}{360} \times \pi \times 15^2 = \frac{675}{4} \pi](https://tex.z-dn.net/?f=%5Cfrac%7B270%7D%7B360%7D%20%5Ctimes%20%5Cpi%20%5Ctimes%2015%5E2%20%3D%20%5Cfrac%7B675%7D%7B4%7D%20%5Cpi)
4. Area of sector 4 = ![\frac{270}{360} \times \pi \times 6^2 = 27 \pi](https://tex.z-dn.net/?f=%5Cfrac%7B270%7D%7B360%7D%20%5Ctimes%20%5Cpi%20%5Ctimes%206%5E2%20%3D%2027%20%5Cpi)
5. Arc length of sector 1 = ![\frac{90}{360} \times 2 \times \pi \times 12 = 6\pi](https://tex.z-dn.net/?f=%5Cfrac%7B90%7D%7B360%7D%20%5Ctimes%202%20%5Ctimes%20%5Cpi%20%5Ctimes%2012%20%3D%206%5Cpi)
6. Arc length of sector 2 = ![\frac{315}{360} \times 2 \times \pi \times 19 = \frac{133}{4} \pi](https://tex.z-dn.net/?f=%5Cfrac%7B315%7D%7B360%7D%20%5Ctimes%202%20%5Ctimes%20%5Cpi%20%5Ctimes%2019%20%3D%20%5Cfrac%7B133%7D%7B4%7D%20%5Cpi%20)
7. Arc length of sector 3 = ![\frac{270}{360} \times 2 \times \pi \times 15 = \frac{45}{2}\pi](https://tex.z-dn.net/?f=%5Cfrac%7B270%7D%7B360%7D%20%5Ctimes%202%20%5Ctimes%20%5Cpi%20%5Ctimes%2015%20%3D%20%5Cfrac%7B45%7D%7B2%7D%5Cpi%20)
8. Arc length of sector 4 = ![\frac{270}{360} \times 2 \times \pi \times 6 = 9\pi](https://tex.z-dn.net/?f=%5Cfrac%7B270%7D%7B360%7D%20%5Ctimes%202%20%5Ctimes%20%5Cpi%20%5Ctimes%206%20%3D%209%5Cpi)
Answer:
6 cm by 14 cm
Step-by-step explanation:
The perimeter of the joined figure will be the sum of the perimeters of rectangles A and B, less the lengths of the sides that are joined. The two joined sides have a total length of ...
(40 cm) +(40 cm) -(68 cm) = 12 cm
Then the length of the joined sides is 6 cm. The length of the other side of the rectangle is the difference between half the perimeter and this, or ...
(40 cm)/2 -6 cm = 14 cm
The length and width of rectangles A and B are 14 cm and 6 cm. When put together, they are joined on the 6 cm side.