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3 years ago

Find the 80th term of the following arithmetic sequence. 17, 26, 35, 44,

Mathematics

1 answer:

ASHA 777 [7]3 years ago

4 0

Answer:

728

Step-by-step explanation:

formula is

Tn= a+(n-1)d

where a is the first term, d is the common difference and n is the term you are looking for

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The following data points represent the number of animal crackers in each kid's lunch box.

OLga [1]

Answer:

IQR = 7

Step-by-step explanation:

To get the interquartile range of the set of data, the following steps must be followed:

Datas 4, 4, 6 , 7, 10 , 11 , 12, 14 ,15

Step 1: Rearrange the datas in ascending or descending order if not arranged.

4, 4, 6 7, 10, 11, 12, 14, 15

Step 2:

We will locate the (N+1/4)the cumulative value of the data where N is the total frequency of the data.

N = 4 + 4 + 6 + 7 + 10 + 11 + 12 + 14 + 15

N = 83

N+1/4 = 83+1/4

= 84/4

= 21st cumulative value

On cumulating the values up to the 21st value or more:

4 + 4 + 6 + 7

= 21

Since the 21st value falls on 7, then the interquartile range of the set of data is 7

3 0

3 years ago

Read 2 more answers

What is the equation of the line that is perpendicular to -2/5x-7 and passes through (4,-1)?

alukav5142 [94]

Step-by-step explanation:

maybe this is not the full expression, as you wrote the line equation in a funny way.

I understand the following :

the line is

y = (-2/5)×x - 7

perpendicular means crossing at a right angle (90 degrees).

the slope of the original line is -2/5.

as in every line equation, the slope is the factor of x. and it expresses the ratio y/x indicating the amount of units y is changing, when x changes a certain amount of units (e.g. when going from one point on the line to another).

the perpendicular slope turns the original y/x ratio upside-down, and also flips the sign.

so, it is 5/2.

the equation for the perpendicular line looks like

y = (5/2)×x + b

now what is b ?

for this we use the specified point on the line : (4, -1)

and we put these values as x and y into the equation :

-1 = (5/2)×4 + b = 5×2 + b = 10 + b

b = -11

and so, the full equation of the perpendicular line is

y = (5/2)×x - 11

3 0

2 years ago

a cell phone company plans to market a new smartphone. they have already sold 612 units durning the first week of the campaign.

Vadim26 [7]

The first term is 612.

The common ratio is 1.08 and

The recursive rule is $a_{n} = a^{n-1} \times r$

<u>Step-by-step explanation:</u>

the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.

<u>The first term :</u>

In geometric sequence, the first term is given as $a_{1}$ .

⇒ $a_{1} = 612$

Now, the geometric sequence follows as 612, 661, ........

<u>The common ratio (r) :</u>

It is the ratio between two consecutive numbers in the sequence.

Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence.

⇒ r = 661 divided by 612

⇒ r = 1.08

<u>To find the recursive rule :</u>

A geometric series is of the form a,ar,ar2,ar3,ar4,ar5........

Here, first term $a_{1} = a$ and other terms are obtained by multiplying by r.

Observe that each term is r times the previous term.
Hence to get nth term we multiply (n−1)th term by r .

The recursive rule is of the form $a_{n} = a^{n-1} \times r$

This is called recursive formula for geometric sequence.

We know that r = 1.08 and $a_{1}$ = 612.

To find the second term $a_{2}$ , use the recursive rule $a_{n} = a^{n-1} \times r$

⇒ $a_{2} = a^{2-1}\times r$

⇒ $a_{2} = a^{1}\times r$

⇒ $a_{2} = 612\times 1.08$

⇒ $a_{2} = 661$

3 0

3 years ago

PLEASE HELP! Which points lie in the second quadrant? Check all that apply?

nevsk [136]

Answer:

is there picture?

Step-by-step explanation:

3 0

2 years ago

a chord of 12cm long of 8cm is away from the of the circle what is the lenght of the chord which is 6cm away from the centre

lana66690 [7]

Answer:

The length of the chord is 16 cm

Step-by-step explanation:

Mathematically, a line from the center of the circle to a chord divides the chord into 2 equal portions

From the first part of the question, we can get the radius of the circle

The radius form the hypotenuse, the two-portions of the chord (12/2 = 6 cm) and the distance from the center to the chord forms the other side of the triangle

Thus, by Pythagoras’ theorem; the square of the hypotenuse equals the sum of the squares of the two other sides

Thus,

r^2 = 8^2 + 6^2

r^2= 64 + 36

r^2 = 100

r = 10 cm

Now, we want to get a chord length which is 6 cm away from the circle center

let the half-portion that forms the right triangle be c

Using Pythagoras’ theorem;

10^2 = 6^2 + c^2

c^2 = 100-36

c^2 = 64

c = 8

The full

length of the chord is 2 * 8 = 16 cm

5 0

3 years ago