The electric field 4cm from the wire is

Given:
charge is distributed uniformly along a long straight wire.
electric field 2cm from the wire is 20n/c
To find:
electric field 4cm from the wire
what is electric field?
Electric field is the region around charge particle or charged body in which if another charge is placed it experiences electrostatic force.An electric field is the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them.





thus the electric field 4cm from the wire is

learn more about electrostatic force from here: brainly.com/question/28166144
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The correct answer is Destructive Interference.Consider the image attached below. Two waves are travelling towards each other. Blue wave always has a positive peak and the red wave always has a negative peak.
Now imagine these waves are moving through a rope. If blue waves will try to move the rope in positive direction, the red wave will pull it down, and thus the two waves will cancel the effect of each other. Thus resulting in a destructive interference.
Answer:
The correct option is (C).
Explanation:
Electric current can be direct or alternating.
The direct current flows only in one direction. It is unidirectional.
The alternating current or an C current reverse its direction periodically.
So, the correct statement regarding the alternating current is (c) i.e. Electrons reverse direction periodically.
Answer:
3600 kg
Explanation:
From the question,
Density = Mass/Volume
D = M/V.............................. Equation 1
Where D = Density of the substance, M = mass of the substance, V = Volume of the subtance.
Make M the subject of the equation
M = D×V ............................ Equation 2
Given: D = 1200 kg/m³, V = 3 m³.
Substitute these values into equation 2
M = 1200×3
M = 3600 kg.
Hence the mass of the substance is 3600 kg
Answer:
D) 1000 m/s
Explanation:

You have the wavelength and frequency, you just need to solve for velocity. You can do this by multiplying each side of the equation by frequency.
Hope this helps.