Oh my lord lol I was do ready to help then I saw numbers
To calculate the gravitational force acting on an object given the mass and the acceleration due to gravity, use the following formula.
Fg = m • g
Fg = 1.3 kg • 9.8 m/s^2
Fg = 12.74 N or about 12.7 N.
The solution is C. 12.7 N.
Answer:
A
Explanation:
Snell's law states:
n₁ sin θ₁ = n₂ sin θ₂
where n is the index of refraction and θ is the angle of incidence (relative to the normal).
The index of refraction of air is approximately 1. So:
1 sin 30° = 1.52 sin θ
θ ≈ 19°
Answer:
![\frac{dy}{dt}=1.2\frac{mi}{min}](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdt%7D%3D1.2%5Cfrac%7Bmi%7D%7Bmin%7D)
Explanation:
We know that the tangent function relates the angle of the right triangle that forms the hot air balloon rising:
![tan\theta=\frac{y}{x}\\y=xtan\theta(1)](https://tex.z-dn.net/?f=tan%5Ctheta%3D%5Cfrac%7By%7D%7Bx%7D%5C%5Cy%3Dxtan%5Ctheta%281%29)
Differentiating (1) with respect to time, we get:
![\frac{dy}{dt}=tan\theta\frac{dx}{dt}+xsec^{2}\theta\frac{d\theta}{dt}\\](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdt%7D%3Dtan%5Ctheta%5Cfrac%7Bdx%7D%7Bdt%7D%2Bxsec%5E%7B2%7D%5Ctheta%5Cfrac%7Bd%5Ctheta%7D%7Bdt%7D%5C%5C)
since x is a constant value. Replacing:
![\frac{dy}{dt}=3mi(sec^{2}\frac{\pi}{3})0.1\frac{rad}{min}\\\frac{dy}{dt}=1.2\frac{mi}{min}](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdt%7D%3D3mi%28sec%5E%7B2%7D%5Cfrac%7B%5Cpi%7D%7B3%7D%290.1%5Cfrac%7Brad%7D%7Bmin%7D%5C%5C%5Cfrac%7Bdy%7D%7Bdt%7D%3D1.2%5Cfrac%7Bmi%7D%7Bmin%7D)