Ok, I love doing these because they're very simple.
F=flour C=corn
m=mild d=medium s=spicy p=pico
c=cheddar j=monterey jack
Fmc
Fmj
Fdc
Fdj
Fsc
Fsj
Fpc
Fpj
8 Flour, which means 8 corn. So that means there are 16 different tacos.
Answer:
-6
Step-by-step explanation:
Answer:
True
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k) = (- 4, - 9), thus
y = a(x + 4)² - 9
To find a substitute the coordinates of the zero (- 7, 0) into the equation.
0 = a(- 7 + 4)² - 9, that is
0 = 9a - 9 ( add 9 to both sides )
9a = 9 ( divide both sides by 9 )
a = 1, thus
y = (x + 4)² - 9 ← expand factor using FOIL
y = x² + 8x + 16 - 9
y = x² + 8x + 7
Answer: 272%
Step-by-step explanation: To write 136/50 as a percent have to remember that 1 equal 100% and that what you need to do is just to multiply the number by 100 and add at the end symbol % .
136/50 * 100 = 2.72 * 100 = 272%
And finally we have:
136/50 as a percent equals 272%
<h3>
Answer: 40</h3>
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Explanation:
JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.
See the diagram below.
The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)
We know that JN = 60
Let x = JQ and y = QN
The ratio of x to y is x/y and this is 2/1
x/y = 2/1
1*x = y*2
x = 2y
Now use the segment addition postulate
JQ + QN = JN
x + y = 60
2y + y = 60
3y = 60
y = 60/3
y = 20
QN = 20
JQ = 2*y = 2*QN = 2*20 = 40
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We have
JQ = 40 and QN = 20
We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.