All categories

2 years ago

Find the missing length of the figure.

Mathematics

1 answer:

Alekssandra [29.7K]2 years ago

5 0

Answer:

x:16

this is related to the Pythagorean theorem

You might be interested in

a woman at a point a on the shore of a circular lake with radius 1.2 mi wants to arrive at the point B diametrically opposite A

kenny6666 [7]

If she arrives by boat;

The distance she needs to row = Lake diameter

Distance = Lake diameter = 2 x Radius

Boat distance = 2 x 2 miles = 4 miles

So;

When moving on foot

The distance that needs to be moved D = Half of the circle circle

∴ D = π × Radius

The distance that needs to be moved D = π × 2 miles = 2π Miles

Arc length = Radius × θ

String length = radius x 2 x sin (θ / 2)

0 ≤ θ ≤ π, 0 ≤ sin (θ / 2) ≤ 1

Learn more here shore of a circular at

brainly.com/question/16597466

#SPJ10

4 0

1 year ago

Solve the formula for the indicated variable <br> A=1/2bh solve for h

vfiekz [6]

Answer:

h=A*2b

Step-by-step explanation:

A=1/2bh

1/2bh=A

1/2bh÷1/2bh=A÷1/2bh (the 1/2b will cancel with the 1/2b on the left leaving h)

h=A*2b

7 0

3 years ago

Find the multiplicative inverse of -2 in mod 7<br>

Elis [28]

Answer:

So something mod 7 is -2
Lets consider what mod does as a commands: If you have 7 and then mod it by 2 ie 7%2 you get 1
Essentially mod is seeing how many times a # goes into the other number and finding the remainder.
In this case we want the remainder of 2: -8%3 =-2
note there is also a mathematical procedural way to solve this.
Rate positively and give brainlist

6 0

2 years ago

1:0,1+2:0,2+3:0,3...+9:0

s2008m [1.1K]

Answer:

Step-by-step explanation:

answeram I righatjfj

6 0

2 years ago

The number of flaws per square yard in a type of carpet material varies with mean 1.4 flaws per square yard and standard deviati

oksian1 [2.3K]

According to the Central Limit Theorem, the distribution of the sample means is approximately normal, with the mean equal to the population mean (1.4 flaws per square yard) and standard deviation given by:
$\frac{\sigma}{ \sqrt{n} }=\frac{1.2}{ \sqrt{178} }=0.09$
The z-score for 1.5 flaws per square yard is:
$z=\frac{1.5-1.4}{0.09}=1.11$
The cumulative probability for a z-score of 1.11 is 0.8665. Therefore the probability that the mean number of flaws exceeds 1.5 per square yard is
1 - 0.8665 = 0.1335.

6 0

3 years ago