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2 years ago

Determine how many oxygeng atoms are in 5.00 g of sample of sodium dichromate, na2cr2o7

Chemistry

1 answer:

vlada-n [284]2 years ago

6 0

The number of oxygen atoms is in 5.00 g of sample of sodium dichromate, Na₂Cr₂O₇ is 1.125 x 10²³ atoms.

<h3>What is sodium dichromate?</h3>

Sodium dichromate is an inorganic compound. It is sued in tanning and mental illness.

The molar mass of sodium = 23 gm

The molar mass of Cr = 51.99 gm

The molar mass of oxygen = 16 gm

Molar mass of Na₂Cr₂O₇ = 2(23) + 2(51.99) + 7(16) = 261.98 gm

Number of moles in 7 gm = mass / molar mass = 7 / 261.98 = 0.0267 moles

1 mole of Na₂Cr₂O₇ contains 7 moles of oxygen, therefore:

The number of moles of oxygen in 0.0267 moles = 0.0267 x 7 = 0.1869 moles

Thus, the number of atoms = 0.1869 x 6.02 x 10^23 = 1.125 x 10²³ atoms.

To learn more about sodium dichromate, refer to the link:

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