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White raven [17]
2 years ago
12

Determine how many oxygeng atoms are in 5.00 g of sample of sodium dichromate, na2cr2o7

Chemistry
1 answer:
vlada-n [284]2 years ago
6 0

The number of oxygen atoms is in 5.00 g of sample of sodium dichromate, Na₂Cr₂O₇ is 1.125 x 10²³ atoms.

<h3>What is sodium dichromate?</h3>

Sodium dichromate is an inorganic compound. It is sued in tanning and mental illness.

The molar mass of sodium = 23 gm

The molar mass of Cr = 51.99 gm

The molar mass of oxygen = 16 gm

Molar mass of Na₂Cr₂O₇ = 2(23) + 2(51.99) + 7(16) = 261.98 gm

Number of moles in 7 gm = mass / molar mass = 7 / 261.98 = 0.0267 moles

1 mole of  Na₂Cr₂O₇ contains 7 moles of oxygen, therefore:

The number of moles of oxygen in 0.0267 moles = 0.0267 x 7 = 0.1869 moles

Thus, the number of atoms = 0.1869 x 6.02 x 10^23 = 1.125 x 10²³ atoms.

To learn more about sodium dichromate, refer to the link:

brainly.com/question/1444529

#SPJ4

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1. If you have 5g of pennies how many dozen pennies do you have?
likoan [24]

Answer:

15.69 dozen

Explanation:

Mass of penny = 5 g

Dozens of penny =..?

Next, we shall convert 5 g to gross. This can be obtained as follow:

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5 g = 1.3075 gross

Thus, 5 g is equivalent to 1.3075 gross.

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3 years ago
Formaldehyde is a carcinogenic volatile organic compound with a permissible exposure level of 0.75 ppm. At this level, how many
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Explanation : Given,

Density of air = 1.2kg/m^3=1.2g/L     (1kg/m^3=1g/L)

First we have to calculate the mass of air.

\text{Mass of air}=\text{Density of air}\times \text{Volume of air}

\text{Mass of air}=1.2g/L\times 6.0L

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Now we have to calculate the amount of formaldehyde.

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Amount of formaldehyde in 7.2 g of formaldehyde = 5.4\times 10^{-6}g

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