Answer:
176.22 nm
Explanation:
= Index of refraction of oil = 1.64
= Wavelength of the light = 578 nm
= minimum thickness of the oil
For destructive interference, we have
![2nt = m \lambda](https://tex.z-dn.net/?f=2nt%20%3D%20m%20%5Clambda)
For minimum thickness, m = 1
![2(1.64)t = (1) (578)\\3.28 t = 578\\t = 176.22 nm](https://tex.z-dn.net/?f=2%281.64%29t%20%3D%20%281%29%20%28578%29%5C%5C3.28%20t%20%3D%20578%5C%5Ct%20%3D%20176.22%20nm)
Force on a proton when they are moving inside the magnetic field is given by
![F = q(v x B)](https://tex.z-dn.net/?f=F%20%3D%20q%28v%20x%20B%29)
so here while protons are going upwards we can say its direction of velocity is towards +Y and magnetic field is towards us which is along +Z direction so they will have force due to this motion.
As per above equation of force we can have direction of force which is along +X direction.
So here both proton will bend towards +X direction and start moving in curved path.
Answer:
i.4.4m/s
ii.5.8m/s
III.5.98m/s
Explanation:
Given Y=70t-16t^2 at t=2
Y= 70(2)-16(2)^2=76m/s
i.at 0.1sec=2.1secs
Y=70(2.1)-16(2.1)^2=76.44m/s
Velocity (76.44-76/.1)=4.4m/s
ii.at t=0.01secs
Y=70(2.01)-16(2.01)^2=76.058m/s
Velocity=(76.056-76/.01)=5.8m/s
ii.at t=0.001
Y=70(2.001)-16(2.001)^2=76.0059m/s
Velocity=(76.0059-76/.001)=5.98m/s
<span>jogs
north for exactly 5.0 min at an average speed of 8.0 km/h.
Convert velocity from km/h to km/min
V = 8.0 km/h * 1h/60min = 2/15 km/min
Distance = V*t = [2/15 km/min]*5min = 2/3 km
He continues
north at a speed of 12.0 km/h for the next 30.0 min.
Again convert km/h to km/min
V = 12.0 km/h * 1h/60min = 1/5 km/min
D = V*t = [1/5 km/min]*30min = 6 km
He then turns
around and jogs south at a speed of 15.0 km/h for 15.0 min.
Position before turning around
X = 2/3 km + 6 km = 20/3 km North
D = V*t = 15.0 km/h *(1/4 h) = 15/4 km
New position: 20/3 km North - 15/4 km South = 35/12 km North
Then he jogs
south for another 20.0 min at 8.0 km/h.
D = V*t = 8.0km/h * [1/3 h] = 8/3 km
New position 35/12 km North - 8/3 km South = 3/12 = 1/4 km North
Total distance jooged = 20/3 km + 15/4 + 8/3 km = 157/12 km = 13.08 km ≈ 13.1 km
He walks the rest of the way
home
He will have to walk 1/4 km = 0.25 km to get home after he finishes jogging
</span>
We can’t answer this you needa to do the scale