Answer:

Explanation:
The electric force between two charged objects is given by:

where:
k is the Coulomb's constant
q1 and q2 are the charges of the two objects
r is their separation
In this problem:
q1 = 2.0 C
q2 = 1.0 C
r = 2 m
So, the electric force is

Answer;
3.45 × 10^-1
Explanation;
-Here we wish to write the number 0.345 as a coefficient times 10 raised to an exponent. To convert to scientific notation, start by moving the decimal place in the number until you have a coefficient between 1 and 10; here it is 3.45.
-The number of places to the left that you had to move the decimal point is the exponent.
= 0.345
= 3.45/10
= 3.45 × 10^-1
Answer:
Where the electric potential is constant, the strength of the electric field is zero.
Explanation:
As a test charge moves in a given direction, the rate of change of the electric potential of the charge gives the potential gradient whose negative value is the same as the value of the electric field. In other words, the negative of the slope or gradient of electric potential (V) in a direction, say x, gives the electric field (Eₓ) in that direction. i.e
Eₓ = - dV / dx ----------(i)
From equation (i) above, if electric potential (V) is constant, then the differential (which is the electric field) gives zero.
<em>Therefore, a constant electric potential means that electric field is zero.</em>
Responder:
T = 0.25 segundos
f = 4 Hz
Explicación:
Paso uno:
datos dados
se nos dice que las partículas tardan 0,25 segundos en completar una vibración
por lo tanto, el período es de 0,25 segundos
¿Qué es un período de vibración?
Un período T es el tiempo necesario para que un ciclo completo de vibración pase por un punto determinado.
la expresión para el período se da a continuación.
T = 1 / f
¿Cuál es la frecuencia de vibración?
Básicamente, se refiere a la frecuencia con la que ocurren las vibraciones.
la frecuencia es una tasa, se expresa como la inversa del período
f = 1 / T
t = 1 / 0.25
f = 4 Hz