Answer:
probability that Caroline buy both CD and fruit = 0.52
Step-by-step explanation:
We have given that the probability of Caroline buys a fruit P = 0.4
So probability of Caroline does not buy the fruit = 1 - 0.4 = 0.6
Probability Caroline buys a CD P = 0.2
So probability of Caroline does not buy the CD = 1 - 0.2 = 0.8
So probability that Caroline does not buy either buy CD or fruit = 0.8×0.6=0.48
So probability that Caroline buy both CD and fruit =1-0.48 = 0.52
Answer:
11:05
Step-by-step explanation:
Answer:
5 bags
Step-by-step explanation:
The volume of the tub is the product of its dimensions:
V = (1.8 m)(0.5 m)(0.25 m) = 0.225 m³
There are 1000 L in 1 m³, so this volume in liters is ...
(0.225 m³)(1000 L/m³) = 225 L
At 50 L per bag, the gardener needs ...
(225 L)/(50 L/bag) = 4.5 bags
The gardener probably cannot purchase a partial bag, so must buy more than is needed.
The gardener must buy 5 bags of compost to fill the tub.
Answer:
f'(x) = 5[1 + f²(x)]
Step-by-step explanation:
By definition, f'(x) = lim h => 0 {[f(x + h) - f(x)]/h}
This was used, together with the given limits:
lim x => 0 f(x) = 0
lim x => 0 f(x)/x = 5,
to determine the derivative of the given function:
f(x + y) = [f(x) + f(y)]/[1 - f(x)f(y)].
The workings are shown in the attachments.
Answer:
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<em><u>h</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>y</u></em><em><u>o</u></em><em><u>u</u></em><em><u> </u></em><em><u>a</u></em><em><u>d</u></em><em><u>d</u></em><em><u> </u></em><em><u>b</u></em><em><u>r</u></em><em><u>a</u></em><em><u>i</u></em><em><u>n</u></em><em><u>l</u></em><em><u>i</u></em><em><u>e</u></em><em><u>s</u></em><em><u>t</u></em><em><u> </u></em><em><u>a</u></em><em><u>n</u></em><em><u>d</u></em><em><u> </u></em><em><u>5</u></em><em><u> </u></em><em><u>s</u></em><em><u>t</u></em><em><u>r</u></em><em><u>a</u></em><em><u>s</u></em>
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Step-by-step explanation:</h2><h2>
<em><u>G</u></em><em><u>o</u></em><em><u>o</u></em><em><u>d</u></em><em><u>b</u></em><em><u>l</u></em><em><u>u</u></em><em><u>c</u></em><em><u>k</u></em></h2>
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<em><u>T</u></em><em><u>H</u></em><em><u>A</u></em><em><u>N</u></em><em><u>K</u></em><em><u> </u></em><em><u>Y</u></em><em><u>O</u></em><em><u>U</u></em><em><u>!</u></em><em><u>!</u></em><em><u>!</u></em></h2>