Answer:
(a) 0.699 kJ/K
(b) -0.671 kJ/K
(c) 0.028 kJ/K
Explanation:
The Refrigerant-134a flows into the evaporator as a saturated liquid-vapor mixture and flows out as a saturated vapor at a saturation pressure of 160 kPa and temperature of -15.64°C (estimated from the Saturated Refrigerant-134a Temperature Table).
(a) The entropy change of the refrigerant (ΔS
) = Q/T
Q = 180 kJ
T
= -15.64 + 273.15 = 257.51 K
ΔS
= Q/T
= 180/257.51 = 0.699 kJ/K
(b) The entropy change (ΔS
) of the cooled space (ΔS
) = -Q/T
Q = -180 kJ
T
= -5 + 273.15 = 268.15 K
ΔS
= Q/T
= -180/268.15 = -0.671 kJ/K
(c) The total entropy change for this process (ΔS
) = ΔS
+ ΔS
= 0.699 - 0.671 = 0.028 kJ/K
Answer:
the atoms of the original substances gain, lose and even share their very own electrons. write the symbols of the elements that form the compound. Write down the valency, and lastly go over valencies. This is all I got so far. I hope this helps
Explanation:
I believe it it false and its the right answer
Answer:
I think it will be He, and Cl2