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svet-max [94.6K]
2 years ago
8

7. Marcie fills a graduated cylinder with 15.0mL of water. Paul finds the mass of a marble to be

Chemistry
1 answer:
Zina [86]2 years ago
5 0

Answer:

<h2>1.7 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

volume = final volume of water - initial volume of water

volume = 16.3 - 15 = 1.3 mL

We have

density =  \frac{2.21}{1.3}  = 1.7 \\

We have the final answer as

<h3>1.7 g/mL</h3>

Hope this helps you

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Given that w for water is 2. 4×10−14 m^2 at 37 °C. Calculate the ph of a neutral aqueous solution at 37 °c, which is the normal
alexgriva [62]

The pH of a neutral aqueous solution at 37°C is 6.8.

<h3>What is Kw? </h3>

Kw is defined as the dissociation, which is also known as self-ionization, constant of water. this is an equilibrium constant, and its expression is:

Kw = [OH⁻] . [H₃O⁺]

Neutral pH determines that the concentrations of OH⁻ and H₃O⁺ are equal.

<h3>Calculation</h3>

Let us suppose concentration of OH and H₃O⁺ is x, to calculate it:

Kw =[OH⁻] . [H₃O⁺] = x²

x² = 2.4 × 10⁻¹⁴ M²

x = 1.5919 × 10⁻⁷ M

Hence, the concentration of OH and H₃O⁺ (x) = [H₃O⁺] = [OH⁻] = 1.5919×10⁻⁷ M

pH = -log[H₃O⁺] = -log( 1.5919×10⁻⁷ M)

pH = 6.8

Thus, we find that the pH of a neutral aqueous solution at 37 °c (which is the normal human body temperature) is 6.8.

learn more about pH:

brainly.com/question/9529394

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3 0
1 year ago
To separate a mixture of iron filings and salt, the most efficient method would be
GaryK [48]

Answer:

Explanation:

Of course you could do the separation chemically. Dissolve the salt up in water, pass thru a filter, wash the iron filings with ethanol, which would encourage the salt to precipitate from solution.

I do hope I helped you! :)

4 0
3 years ago
A compound of a transition metal and iodine is 56.7% metal by mass.How many grams of the metal can be obtained from 630 g of thi
erma4kov [3.2K]

Answer:

357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine

Explanation:

In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.

Given mass of sample compound = 630 g

Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;

56.7 % = 56.7/100 = 0.567

Mass of transition metal = 0.567 * 630 = 357.21 g

Therefore, the mass of the transition metal  present in 630 g of the compound is approximately 357 g

4 0
3 years ago
People ask me if you could pick any song that described you from a boys POV what would it be??? i always say "she's country by j
lions [1.4K]

Lovely song just asking is there a question so I don't get hate for not knowing rather there's a question or not

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3 years ago
How many grams of CO2 are in 2.1 mol of the compound? a) 21.0g c) 66.0g
Lilit [14]
1 mole CO2 = 44.0096 grams CO2


<span>2.1 mol CO2 x (44.0096 grams CO2/1 mole CO2) = 92.4 grams CO2</span>
8 0
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