The area of the rectangle is changing at
0.75 sq.cm/min
Let
x
and
y
be the base and height of the rectangle.
x
=
0.5
cm is constant :. dx/dt=0#. Area of the rectangle
is
A
=
x
⋅
y
. Differentiating both sides we get
d
A
d
t
=
d
x
d
t
⋅
y
+
d
y
d
t
⋅
x
;
y
=
1.5
,
d
y
d
t
=
1.5
cm /min.
∴
d
A
d
t
=
0
⋅
1.5
+
1.5
⋅
0.5
=
0.75
sq.cm/min.
The area of the rectangle is changing at
0.75
sq.cm/min
327421537466 and yes i did all of this that fast
Answer:
z1 + z2 = 3
Step-by-step explanation:
Since we are given z1 = 2 + √(3)i and z2 = 1 – √(3)i. The sum of z1 + z2 would be:
(2 + √(3)i) + (1 – √(3)i) = 2 + √(3)i + 1 – √(3)i = 2 + 1 + √(3)i – √(3)i = 3
Hence, z1 + z2 = 3.
Answer:
y=2x-7
Step-by-step explanation:
y-y1=m(x-x1)
y-(-1)=2(x-3)
y+1=2x-6
y=2x-6-1
y=2x-7