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3 years ago

Plz Answer Fam & Con Chemistry (8TH GRADE)

Chemistry

2 answers:

Fantom [35]3 years ago

5 0

Claw technique is what is represented

olga_2 [115]3 years ago

3 0

Answer:

claw techniques

Explanation:

because it is

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a covalent bond involves: a. transferring of b. sharing protons c. transferring protons d. sharing electrons

Bas_tet [7]

A covalent bond involves: <u>d. sharing electrons</u>

The atoms of a molecule are held together by electrical forces that hold the atoms together, this is due to the electrical attraction between the electrons of the atom of one element and the nucleus of the other atom, this force of attraction is called covalent bond.

A covalent bond involves the sharing of electrons that are in the last energy layer of the atoms because they are the most likely or willing to be shared.

An example of a covalent bond is the bond between a hydrogen atom and a carbon atom in methane.

The atom is the smallest part of the composition of matter, it is indivisible and is composed of a nucleus that has protons and neutrons, and around the nucleus there are the electrons.

Learn more about the atom at: brainly.com/question/17545314

#SPJ4

8 0

1 year ago

I know how to solve it with D=M/V and M1V1 however the answer isn’t correct. Help me please

lara31 [8.8K]

Answer:

23.28 g of O2.

Explanation:

We'll begin by calculating the mass of hexane. This can obtain as follow:

Volume of hexane = 10 mL

Density of hexane = 0.66 g/mL

Mass of hexane =?

Density = mass /volume

0.66 = mass of hexane /10

Cross multiply

Mass of hexane = 0.66 x 10

Mass of hexane = 6.6 g

Next, we shall write the balanced equation for the reaction. This is given below:

2C6H14 + 19O2 —> 12CO2 + 14H2O

Next, we shall determine the masses of C6H14 and O2 that reacted from the balanced equation. This can be obtained as follow:

Molar mass of C6H14 = (12.01x6) + (1.008 x 14)

= 72.06 + 14.112

= 86.172 g/mol

Mass of C6H14 from the balanced equation = 2 x 86.172 = 172.344 g

Molar mass of O2 = 16x2 = 32 g/mol

Mass of O2 from the balanced equation = 19 x 32 = 608 g

From the balanced equation above,

172.344 g of C6H14 reacted with 608 g of O2.

Finally, we shall determine the mass of O2 needed to react with 10 mL (i.e 6.6 g) of hexane, C6H14. This can be obtained as follow:

From the balanced equation above,

172.344 g of C6H14 reacted with 608 g of O2.

Therefore, 6.6 g of C6H14 will react with = (6.6 x 608)/172.344 = 23.28 g of O2.

Therefore, 23.28 g of O2 is needed for the reaction.

8 0

3 years ago

An iron ore was found to contain 92.0% pyrite (fool's gold). Pyrite has the formula FeS2and is 46.5% iron. How many grams of iro

Liula [17]

Firstly calculate the grams in the last 8 percent before moving onto the pyrite section.
50.8x0.08=4.064g
We know that iron ore in this case has 92 percent pyrite which contains 46.5 percent iron so we do 50.8x0.92=46.736g from this we need to find 46.5 percent of the iron content in the 92 percent pyrite section then add this answer to the 8 percent of iron ore we found at the start.46.736x0.465=21.73224g
21.73224g+4.064=25.79624g of iron ore 25.8g(3sf)

4 0

3 years ago

Experiment ideas I could win a lot of money from school

AleksAgata [21]

I am not all understood but for the school to earn money you can:

make

--a raffle

--lotto

-- yard sale

-- class photo

-- origami for sale or something

-- buffet or food sale (example all Friday ice cream sale, 2 livre ice cream)

6 0

3 years ago

The combustion of ammonia in the presence of excess oxygen yields no2 and h2o: 4 nh3 (g) + 7 o2 (g) â 4 no2 (g) + 6 h2o (g) the

VLD [36.1K]

The answer would be 118.68 g.
Explanation for this is:4 moles of NH3 give 4 moles of NO2
so 1mole of NH3 will give 1 mole of NO2
43.9 grams of NH3 contains 2.58 moles
so 2.58 moles will be produced of NO2
which is 118.7 grams this the amount of oxygen that is used.

8 0

3 years ago