Answer:
The answers are,
-3, -7
-2, 4
0, 2
2, 8
3, 11
Step-by-step explanation:
You just plug in the domain values into the equation and solve for f(x), so your domain number is your x value and the y value(f(x) value) is the answer
15 + 16 + 15 + 8 + 6 = 60 divided by 5 = 12
Answer is D
Answer:
Similarly: yes
Similarly Statement: LMNO ≈ ZWXY
Scale factor: 2/7
Answered by GAUTHMATH
Average (mean) = (sum of all the data) / (# of data)
sum of all the data = (average)(# of data)
Thus for 100 students with an average of 93,
sum of all data = (93)(100) = 9300
and for 300 students with an average of 75,
sum of all data = (75)(300) = 22500
Therefore you would expect the overall average to be
(9300 + 22500) / (100 + 300) = 79.5 %
Now if there are x # of advanced students and y # of regular students, then
x + y = 90 (total # of students) and 93x + 75y = 87(x + y) (overall average)
The second equation can be simplified to x - 2y = 0
Subtracting the two equations yields
x = 60 and y = 90
Therefore you would need 60 advanced and 30 regular students.
