A 200 g mass, attached to a 30 cm long string, travels at a speed of 1.3 ms-1 along horizontal circular path. Relative to the ce
1 answer:
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Answer:
The minimum speed of the box bottom of the incline so that it will reach the skier is 8.19 m/s.
Explanation:
It is given that,
Mass of the box, m = 2.2 kg
The box is inclined at an angle of 30 degrees
Vertical distance, d = 3.1 m
The coefficient of friction,
Using the work energy theorem, the loss of kinetic energy is equal to the sum of gain in potential energy and the work done against friction.
W is the work done by the friction.
v = 8.19 m/s
So, the speed of the box is 8.19 m/s. Hence, this is the required solution.
Answer:
a) 20 m/s
b) No
Explanation:
a)
Mr. G needs to run x= 200 m in t = 10 seconds to catch the bus.
Knowing the speed is computed as
We have
b)
The fastest human can run 12 m/s, so Mr. G won't be able to catch the bus because he needs to run faster than that