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3 years ago

How do insects aid in crime scene investigations

Physics

1 answer:

monitta3 years ago

8 0

Answer:

They can figure out when the person died, possibly the nature of crime, it can also detect if the body was moved in certain area.

Explanation:

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How many drops of water are in a 1.0 L bottle? (Hint: Start by estimating the diameter of a drop of water.)

o-na [289]

Answer:

N = 2000 drops approx with 1 cm diameter each

Explanation:

Let the diameter of one drop is 1 cm

so volume of one drop is given by

$V = \frac{1}{6}\pi d^3$

now we have

$V = \frac{1}{6}\pi(0.01)^3$

$V = 0.53 \times 10^{-6} m^3$

now in 1L of liquid let say N drops are there

so we have

$1L = 10^{-3} m^3$

now we have

$N = \frac{10^{-3}}{0.53 \times 10^{-6}}$

$N = 2\times 10^3$

so it will have approx 2000 drops in it with diameter 1 cm each drop

7 0

3 years ago

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The magnetic field produced by the solenoid in a magnetic resonance imaging (MRI) system designed for measurements on whole huma

Vesna [10]

Answer:

Number of turns per unit length will be $n=2.786\times 10^4turns/m$

Explanation:

We have given that strength of the magnetic field produced by the solenoid B = 7 T

Current in the solenoid i = 200 A

Let the number of turns per unit length is n

Magnetic field due to solenoid is given as $B=\mu ni$ here $\mu$ is permeability of free space n is number of turns per unit length and i is current

So $7=4\pi \times 10^{-7}\times n\times 200$

$n=2.786\times 10^4turns/m$

7 0

3 years ago

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Which is the best description of inertia? Inertia is

valentinak56 [21]

Answer:

The best description of inertia is an objects velocity

8 0

3 years ago

7. An object can be accelerating even if its speed is

steposvetlana [31]

Answer:

I think that the answer might be d

4 0

3 years ago

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A wire of length 5mm and Diameter 2m extends by 0.25 when a force of 50N was use. calculate the

bazaltina [42]

Answer and Explanation:

Data provided in the question

Force = 50N

Length = 5mm

diameter = 2.0m = $2\times 10^{-3}$

Extended by = 0.25mm = $0.25\times 10^{-3}$

Based on the above information, the calculation is as follows

a. The Stress of the wire is

$= \frac{force\ applied}{area\ of \ circle}$

here area of circle = perpendicular to the are i.e cross-sectional i.e

= $\frac{\pi d^{2}}{4}$

= $\frac{\pi(2\times 10^{-3})^2}{4}$

Now place these above values to the above formula

$= \frac{4\times 50}{\pi\times 4 \times 10^{-6}} \\\\ = \frac{50}{\pi}$

= 15.92 MPa

As 1Pa = 1 by N m^2

So,

MPa = 10^6 N m^2

b. Now the strain of the wire is

$= \frac{Change\ in\ length}{initial\ length} \\\\ = \frac{0.25\times 10^{-3}}{5}$

= $5 \times 10^{-5}$

3 0

3 years ago