What is the automated system that uses an automated work cell controlled by electronic signals from a common centralized compute
1 answer:
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To solve this problem we will apply the concepts related to kinetic energy and energy conservation. The kinetic energy will be expressed in terms of mass and speed, as well as load and voltage. From this last expression we will find the charges by electron and by Helium nucleus.
a ) Kinetic Energy is given as
Replacing with our values we have that
Therefore the kinetic energy of the helium nucleus is
PART B) Now for calculate the electron volts we use the kinetic energy as a expression between the charge and the voltage, that is
Here,
q = Charge of an electron
V = Voltage
Rearranging to find the potential we have,
Therefore the kinetic energy in electron vols is
PART C) Applying the same relationship but now using the Helium core load, we will have to
Here,
Q = Charge of a helium nucleus
V = Voltage
Rearranging to find the potential we have
But we need to note that the charge is equal to the number of charge for the unit charge, then
Now replacing we have that
Therefore the voltage applied is 371875V
Answer:
The maximum wavelength of light that could liberate electrons from the aluminum metal is 303.7 nm
Explanation:
Given;
wavelength of the UV light, λ = 248 nm = 248 x 10⁻⁹ m
maximum kinetic energy of the ejected electron, K.E = 0.92 eV
let the work function of the aluminum metal = Ф
Apply photoelectric equation:
E = K.E + Ф
Where;
Ф is the minimum energy needed to eject electron the aluminum metal
E is the energy of the incident light
The energy of the incident light is calculated as follows;
The work function of the aluminum metal is calculated as;
Ф = E - K.E
Ф = 8.02 x 10⁻¹⁹ - (0.92 x 1.602 x 10⁻¹⁹)
Ф = 8.02 x 10⁻¹⁹ J - 1.474 x 10⁻¹⁹ J
Ф = 6.546 x 10⁻¹⁹ J
The maximum wavelength of light that could liberate electrons from the aluminum metal is calculated as;