Answer:
43.83 nC
Explanation:
We know Q = ε₀Ψ where Q = charge enclosed by the cubic box, ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m and Ψ = net electric flux through cubic box = 4950 Nm²/C
So, substituting the values of the variables into the equation, we have
Q = ε₀Ψ
= 8.854 × 10⁻¹² F/m × 4950 Nm²/C
= 43827.3 × 10⁻¹² C = 4.38273 × 10⁻⁸ C
= 43.8273 × 10⁻⁹ C
= 43.8273 nC
≅ 43.83 nC
Answer:
B
Explanation:
Because according to the bolye law . Pressure is inversely propotional to volume . So higher the pressure lower the volume. P1×V1=P2×V2
Answer:
2KOH(aq) + H2SO4(aq) ⇒ K2SO4(aq) + 2H2O(l)
Explanation:
The reaction is a neutralization reaction since an acid, aqeous H2SO4 reacts completely with an appropriate amount of alkali, aqueous KOH to produce salt, aqueous K2SO4 and liquid water, H2O only.
2KOH(aq) + H2SO4(aq) ⇒ K2SO4(aq) + 2H2O(l)
Alkali + Acid → Salt + Water.
During this reaction, 2 moles of KOH neutralize 1 mole of H2SO4 to yield 1 mole of K2SO4 and 2 moles of H2O.
Explanation:
Metals get charged by induction ,the charges are transferred from the electroscope causing earthing: Charges on the electroscope induce opposite charges on the conductor.
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Answer: a)5.73 *10^-6 C/m^2; b)648*10· N/C c)56.5 *10^3 Nm^2/C
Explanation: Considering the definition of surface charge density as:
σ = Q/ area of sphere
so Q = σ * 4*π* R^2outer
The new Q at the outer radius is: Q initial -0.5 microC =5 micro C
The Electric with the new outer charge is equal to:
E= k*Q / R^2outer= 9 10^9* 5 microC/(0.25m)^2= 648*10^3 N/C
Finally the flux corresponding to the internal charge is equal to
By using Gauss law, the total flux is equal to net change divided ε0
so this is 0.5 microC/ ε0= 56.5 *10^3 Nm^2/C
