Answer:
Explanation:
From the question we are told that:
Radius 
Charge Density 
Distance 
Generally the equation for electric field is mathematically given by
<span>(6.0x10^-22, -1.40x10^-21, 0) kg*m/s
Momentum is a conserved quantity. The total momentum of the system before and after the interactions will not change. So, let's look at the momentum before the interaction.
(3.2x10^-21, 0, 0) kg*m/s and (0,0,0) kg*m/s
After the interaction
(2.6x10^-21, 1.40x10^-21, 0) kg*m/s
and the other proton has to have a momentum that when added to this momentum equal the original value. Since the y and z vectors were initially 0, all we need for the y and x vector values of the result is to negate them. The x vector value will be
3.2x10^-21 - 2.6x10^-21 = 0.6x10^21 = 6.0x10^-22. So the other proton will have a momentum of
(6.0x10^-22, -1.40x10^-21, 0) kg*m/s</span>
Answer: Two marbles separated by 300 kilometers
Explanation: Hope i helped have a great day and please mark brainliest i would appreciate it!
