Question

Bring 8/(a-x) to a denominator of x-a

Answer 1

Answer:

$-\frac{8}{x-a}$

Step-by-step explanation:

$\frac{8}{a-x}$

we can take common factor of -1 in the denominator

$\frac{8}{-(-a+x)}=\frac{8}{-(x-a)}$

and now multiply and divide by -1

$\frac{8}{-(x-a)}\cdot \frac{-1}{-1}=\frac{-8}{x-a}=-\frac{8}{x-a}$