Answer:
Step-by-step explanation:
36/6 · 2 + 1
6 ·2 + 1
12 + 1 = 13
answer is 13
I think its c your welcome
Answer:
1,778
Step-by-step explanation:
Let C and S represent the cost and salvage value of Truck B, respectively. Let X represent the number of miles per year that answers the question.
Truck A's cost for 10 years is ...
A = C+600 +(0.06)(2.25)(10X) -(S+200)
Truck B's cost for 10 years is ...
B = C +(0.07)(2.25)(10X) -S
We want to find X such that Truck A's cost is lower, so ...
C -S +1.35X +400 < C -S +1.575X
400 < 0.225X
1777 7/9 < X
1778 miles driven per year (or more) makes Truck A a better option.
June is 30 days
30-12=18 days
July is 31 days
August is 30 days
Time=18+31+30=79 days
A=2,750×(1+0.035÷365)^(79)
A=2,770.91
Interest earned
I=A-p
I=2770.91-2750
I==20.91
