The area of the shape shown in the image which is in the shape of kite figure is 168 squared centimeters.
<h3>What is the area of the kite figure?</h3>
The area of the kite figure is half of the product of its diagonals. Area of kite figure can be find out using the following formula.
Here, p and q are the diagonals of the kite.
The length of the first diagonal of the kite figure is,
p=6+15
p=21 cm
The length of the second diagonal of the kite figure is,
q=8+8
q=16 cm
Thus, the area of kite figure is:
Thus, the area of the shape shown in the image which is in the shape of kite figure is 168 squared centimeters.
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Answer: 7.012 x 10−8 ==> Option 3
Step-by-step explanation:
(3.012 x 10−8) + (4 x 10−8)=
(3.012+4) x 10−8=
(3.012+4.000) x 10−8=7.012 x 10−8 ==> Option 3
3x +2y= 11 ----1
x -2 = -4y ---- 2
Equation 2 times by 3
3x -6 = -12y
Subracting 2-1
3x-6=-12y
3x-11=-2y
Leaving
5=-10y
y= -1/2
Hence
B. is the solution
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Answer:
Step-by-step explanation:
use distance formula (x2-x1) + (y2-y1)-----> (4-1)+ (5-Y)=3x3+ 5y=
6+5y=6/5=1.2
y=1.2?
Answers:
x = 8
y = 15*sqrt(2)
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Explanation:
This is a 45-45-90 triangle. The right triangle is isosceles.
This means the two legs 3x-9 and x+7 are the same length
3x-9 = x+7
3x-x = 7+9
2x = 16
x = 16/2
x = 8
If x = 8, then each leg is...
3x-9 = 3(8)-9 = 24-9 = 15
x+7 = 8+7 = 15
Each leg is 15 units long to help confirm we have the correct x value.
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The hypotenuse y is exactly sqrt(2) times that of the leg length.
Therefore, y = 15*sqrt(2) since earlier we found each leg is 15 units long.
15*sqrt(2) = 21.213 approximately
