Answer:
y = -3x + 4
Step-by-step explanation:
sorry im late
but all you have to do is isolate the y
so to do that we have to get rid of the 3x
3x + y = 4
in order to do that we have to subtract 3x from both sides of the equal sign since it is positive and being added to the y
3x + y = 4
-3x -3x
y = -3x + 4
and now y is isolated
Answer:
8x + 13
Step-by-step explanation:
"Like terms" means the same kind of algebraic expression...the 6x and the 2x are "like terms" because they both have an x in them. The 9 and the 4 are both constants, which means they are plain numbers. So 6x and 2x is 8x .
9+4 is 13 just like elementary school.
So all together,
6x + 9 + 2x + 4
6x + 2x + 9 + 4
8x + 13
We can rearrange the terms because the problem has all addition in between the terms.
Answer: Craig's household use of water during the billing period = 129 CFC
Explanation:
Since we have given that
Craig's June water meter's previous reading =6372 CFC
Craig's water meter's present reading =6501 CFC
Craig's household use during the billing period =6501 -6372= 129 CFC
So, we get that
Craig's household use of water during the billing period = 129 CFC
The correct answer is 673
9+4= 13
5 turns into a 6 so it’s 6+1 = 7
3+3 = 9
Logarithmic differentiation means tAke logarithm of both sides to make the function easier to find the derivative.
y = (sinx)^lnx
ln(y) = ln((sinx)^lnx)
power rule logarithm
ln(y) = ln(x) ln(sinx)
Take derivative
y'/y = ln(sinx)(1/x) + ln(x) cosx/sinx
multiply both sides by y
y' = y( ln(sinx)/x + ln(x)cotx )
remember y = (sinx)^lnx
sub this in for y
y' = (ln(sinx)/x + ln(x)cotx)(sinx)^lnx
