Ask question

Ask question

All categories

3 years ago

7

Ephemeral services corporation (esco) knows that nine other companies besides esco are bidding for a $900,000 government contrac

t. each company has an equal chance of being awarded the contract. if esco has already spent $100,000 in developing its bidding proposal, what is its expected net profit?
a. $10,000

b. $0

c. $100,000

d. $90,000

1 answer:

EastWind [94]3 years ago

4 0

Answer:

c. $100,000

Step-by-step explanation:

Calculation of the expected net profit of Ephemeral services corporation

Since we are been told that 9 other companies besides esco are as well bidding for the $900,000 government contract, it means we have to find the expected net profit by dividing 1 by 9×$900,000 .Thus ESCO can only expect to cover its sunk cost.

Hence ,

E(X) = (1/9) × $900,000

E(X)=0.111111111×$900,000

E(X)= $100,000

Therefore the expected net profit would be $100,000

You might be interested in

Please help me with this equation, the values are in the file <br><br> x + B = Fx - Dx + H

Olin [163]

Answer:

x = -6

Step-by-step explanation:

B = 2

F = 6

D = 4

H = 8

x + B = Fx - Dx + H

x + 2 = 6x - 4x + 8

x + 2 = 2x + 8

-x = 6

x = -6

3 0

3 years ago

Read 2 more answers

Find exact values for sin θ, cos θ and tan θ if csc θ = 3/2 and cos θ < 0.

kumpel [21]

Answer:

Part 1) $sin(\theta)=\frac{2}{3}$

Par 2) $cos(\theta)=-\frac{\sqrt{5}}{3}$

Part 3) $tan(\theta)=-\frac{2\sqrt{5}}{5}$

Step-by-step explanation:

step 1

Find the $sin(\theta)$

we have

$csc(\theta)=\frac{3}{2}$

Remember that

$csc(\theta)=\frac{1}{sin(\theta)}$

therefore

$sin(\theta)=\frac{2}{3}$

step 2

Find the $cos(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$sin(\theta)=\frac{2}{3}$

substitute

$(\frac{2}{3})^{2} +cos^{2}(\theta)=1$

$\frac{4}{9} +cos^{2}(\theta)=1$

$cos^{2}(\theta)=1-\frac{4}{9}$

$cos^{2}(\theta)=\frac{5}{9}$

square root both sides

$cos(\theta)=\pm\frac{\sqrt{5}}{3}$

we have that

$cos(\theta) < 0$ ---> given problem

so

$cos(\theta)=-\frac{\sqrt{5}}{3}$

step 3

Find the $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=\frac{2}{3}$

$cos(\theta)=-\frac{\sqrt{5}}{3}$

substitute

$tan(\theta)=\frac{2}{3}:-\frac{\sqrt{5}}{3}=-\frac{2}{\sqrt{5}}$

Simplify

$tan(\theta)=-\frac{2\sqrt{5}}{5}$

6 0

3 years ago

If sin (90° - α) = BC /CA,write down the ratio of sina.

Papessa [141]

Answer:

Step-by-step explanation:

sin(90-a)=cos

cos = angle adjacent

theta=BC/CA

7 0

2 years ago

Find the gradient of the line segment between the points (-4,1) and (2,4). Give your answer in its simplest form.

andrew-mc [135]

Answer:

<h2> $\frac{1}{2}$ </h2>

Solution,

Let the points be A and B

A(-4 , 1)------>( X1, y1)

B(2,4)---------->( x2, y2)

Now,

Gradient:

$\frac{y2 - y1}{x2 - x1}$

$\frac{4 - 1}{2 - ( - 4)}$

$\frac{3}{2 + 4}$

$\frac{3}{6}$

$\frac{1}{2}$

Hope this helps...

Good luck on your assignment...

3 0

3 years ago

Read 2 more answers

What pattern do you notice in the numbers below? 1 = 1 × 1, and 1 × 1 × 1, and 1 × 1 × 1 64 = 8 × 8, and 4 × 4 × 4 729 = 27 × 27

11111nata11111 [884]

Answer:

<h3>C. They are both perfect squares and perfect cubes.</h3>

Step-by-step explanation:

Perfect squares are numbers that their square root can be found easily without any remainder.

Given the following patterns;

1*1 = 1 and 1*1*1 = 1

It can be seen that 1 is 1 perfect square since 1*1 = 1² = 1

Also 1 is perfect cube since 1*1*1 = 1³ = 1 (cube of the value gives 1)

Similarly for the expression;

8*8 = 64

8² = 64 (since the square of 8 gives 64, then 64 is known to be a perfect square)

Also 4*4*4 = 64

i.e 4³ = 64 (This shows that the cube root of 64 is 4 making it a perfect cube since we can get a whole number for the cube root of 64)

The same is applicable for other expressions 729 = 27 × 27, and 9 × 9 × 9, 4,096 = 64 × 64, and 16 × 16 × 16

This values are easily expressed as a constant multiple of a number showing that they are both perfect squares and perfect cubes.

4 0

3 years ago