Which group on the periodic table would have zero electronegativity because they have a full octet?
1 answer:
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Answer:
k' = (2.0345 × 10⁻⁸) M/s.
Explanation:
Beer-Lambert's law explains that Absorbance is directly proportional to the concentration of the substrate under consideration.
A ∝c
A = εlc
where ε = molar absorptivity constant = 87,000 M⁻¹cm⁻¹
l = path length of the solution that the light passes through in cm = 1 cm for most cases.
c = concentration of the substrate.
In terms of rate terms,
A' = εlc'
where A' has units of Absorbance/s
c' = rate of reaction, units of concentration/s
A' = εlc'
From the graph, the slope of the graph = 0.00177 Absorbance/s
0.00177 = 87000 × 1 × c'
c' = (0.00177/87000)
c' = (2.0345 × 10⁻⁸) M/s.
This value is the pseudo rate constant, k'.
Hope this Helps!!!
