Answer:
2.2mL
Explanation:
First, let us analyse what was given from the question:
C1 = 2.09M
V1 =?
C2 = 0.046M
V2 =100mL
Using dilution formula (C1V1 = C2V2), we can calculate the volume of the original solution as follows:
C1V1 = C2V2
2.09 x V1 = 0.046 x 100
Divide both side by the coefficient of V1 ie 2.09, we have:
V1 = (0.046 x 100) / 2.09
V1 = 2.2mL
The gas is NH₃.
H₂ doesn't dissolve readily in water, SO₂ gives an acidic solution in water.
The solid residue is Fe(OH)₂.
FeSO₄ and Na₂SO₄ are soluble in water.
The answer is C.
132 g of C , 22 g of H , 176 g of O
132 + 22 + 176 => 330 g <span>of the substance
</span>Now convert the masses in <span>moles :
</span>
C = 12.0 u H = 1.0 u O = 16.0 u
C = 132 / 12.0 => 11 moles
H = 22 / 1.0 => 22 moles
O = 176 / 16.0 => 11 moles
Using the values obtained the lowest proportion in mols of elements present, simply divide the values found for the least of them<span>:
</span>
C = 11 / 11 => 1
H = 22 / 11 => 2
O = 11 / 11 => 1
formula empirically <span>is : CH</span>₂O
hope this helps!
The answer is A i think if it’s wrong someone correct me
