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2 years ago

The minimum amount of methyl benzoate needed to trigger an alert for a drug dog is on the order of:

Chemistry

1 answer:

olga_2 [115]2 years ago

3 0

To trigger a drug-dog alert, the necessary threshold level would be around 1 to 10 micrograms of methyl benzoate.

In the 1999 Furton study, it was stated that it would take 500 milligrams of cocaine in order to emit 1 to 10 micrograms of Methyl Benzoate.

A colorless liquid that is poorly soluble in water is one of the properties of methyl benzoate.

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Magnesium (24.30g) reacts with hydrogen chloride (xg) to produce hydrogen gas(2.04g) and magnesium chloride (96.90g). How much h

weqwewe [10]

Answer:

Answer is 74.42 if you are on cK-12.

Explanation:

6 0

2 years ago

Read 2 more answers

Which statement below correctly describes the relationship between Q and K for both reactions? Are these reactions spontaneous a

nikklg [1K]

Answer:

Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.

Explanation:

Hello,

In this case, the undergoing chemical reactions with their proper Gibbs free energy of reaction are:

$A->B;\Delta _rG^o=-13 kJ/mol$

$C ->D ;\Delta _rG^o=3.5 kJ/mol$

The cellular concentrations are as follows: [A] = 0.050 mM, [B] = 4.0 mM, [C] = 0.060 mM and [D] = 0.010 mM.

For each case, the reaction quotient is:

$Q_1=\frac{4.0mM}{0.050mM}=80\\ Q_2=\frac{0.010mM}{0.060mM}=0.167$

A typical temperature at a cell is about 30°C, in such a way, the equilibrium constants are:

$K_1=exp(-\frac{-13000J/mol}{8.314J/mol*K*303.15K} )=173.8\\K_2=exp(-\frac{3500J/mol}{8.314J/mol*K*303.15K} )=0.249$

Therefore, Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.

Best regards.

6 0

2 years ago

4) What is one advantage of using non-renewable resources?

vlabodo [156]

Answer:

The main advantages of non-renewable energies is that they are abundant and affordable. For example, oil and diesel are still good choices for powering vehicles. Non-renewable energy is cost effective and easier to product and use.

Explanation:

there yah go

5 0

2 years ago

QUESTION THREE

BartSMP [9]

Answer:

Odds to be given for an event that either Romance or Downhill wins is 11:4

Explanation:

Given an odd, r = a : b. The probability of the odd, r can be determined by;

Pr(r) = $\frac{a}{b}$ ÷ (

So that;

Odd that Romance will win = 2:3

Pr(R) = $\frac{2}{3}$ ÷ (

= $\frac{2}{3}$ ÷ $\frac{5}{3}$

= $\frac{2}{5}$

Odd that Downhill will win = 1:2

Pr(D) = $\frac{1}{2}$ ÷ (

= $\frac{1}{2}$ ÷ $\frac{3}{2}$

= $\frac{1}{3}$

The probability that either Romance or Downhill will win is;

Pr(R) + Pr(D) = $\frac{2}{5}$ + $\frac{1}{3}$

= $\frac{11}{15}$

The probability that neither Romance nor Downhill will win is;

Pr(neither R nor D) = (1 - $\frac{11}{15}$ )

= $\frac{4}{15}$

The odds to be given for an event that either Romance or Downhill wins can be determined by;

= Pr(Pr(R) + Pr(D)) ÷ Pr(neither R nor D)

= $\frac{11}{15}$ ÷ $\frac{4}{15}$

= $\frac{11}{4}$

Therefore, odds to be given for an event that either Romance or Downhill wins is 11:4

8 0

2 years ago

When the nail was copper-plated in Part III of the lab, what element do you think was reduced? Explain your answer in complete s

Jet001 [13]

Reduction always results in a lowering of the oxidation number. The reaction of the system above is written as:

Cu2+(aq) + Fe(s) --> Cu(s) + Fe2+(aq)

From the reaction, we see that copper goes from the +2 to a neutral charge. Lowering of the oxidation number happens so this is the element that is being reduced.

6 0

2 years ago