Question

What mass of iron would be required to react with 10.0L of O2 gas?

Answer 1

33.2 g of iron (Fe)

Explanation:

We have the following chemical reaction in which iron react with oxygen to form the iron (III) oxide:

4 Fe + 3 O₂ → 2 Fe₂O₃

number of moles = volume / 22.4 (L/mole)

number of moles of O₂ = 10 / 22.4

number of moles of O₂ = 0.446 moles

Taking in account the chemical reaction we devise the following reasoning:

if           4 moles of Fe react with 3 moles of O₂

then     X moles of Fe react with 0.446 moles of O₂

X = (4 × 0.446) / 3 = 0.595 moles of Fe

number of moles = mass / molar weight

mass =  number of moles × molar weight

mass of Fe = 0.595 × 55.8

mass of Fe = 33.2 g

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