Answer:
0.238 M
Explanation:
A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.
C₁.V₁ = C₂.V₂
C₁ × 24.00 mL = 0.220 M × 52.00 mL
C₁ = 0.477 M
The concentration of Pb(ClO₃)₂ is:
First, we construct the reaction equation:
Na₂SO₃ + 2HCl → 2NaCl + SO₂ + H₂O
H₂SO₃ is formed as an intermediate but decomposes to water and SO₂ gas.
1 moles Carbon to grams = 12.0107 grams
2 moles Carbon to grams = 24.0214 grams
3 moles Carbon to grams = 36.0321 grams
4 moles Carbon to grams = 48.0428 grams
5 moles Carbon to grams = 60.0535 grams
6 moles Carbon to grams = 72.0642 grams
7 moles Carbon to grams = 84.0749 grams
8 moles Carbon to grams = 96.0856 grams
9 moles Carbon to grams = 108.0963 grams
10 moles Carbon to grams = 120.107 grams
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