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Maurinko [17]
3 years ago
9

Which of the following groups contain three elements with stable electron configurations?

Physics
2 answers:
Wewaii [24]3 years ago
6 0

Answer:

B. helium, xenon, neon

Explanation:

barxatty [35]3 years ago
3 0
B is the correct answer because Helium, Xenon, and Neon are all Noble Gases at Group 18, which means they contain the full 8 electrons they need meaning they all have stable electron configurations.
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Hi guys . I'm having some troubles with physics and chemistry .
Otrada [13]

Answer:

physics and math tutor

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Explanation:

hii! for PTM(physics and math tutor) you simply type in the search bar for example in. physics Units and measurements past papers.Then the first option would be PTM(physics and math tutor) and you click on it and it would give you on the left side Revision Notes, flashcards and practice questions. This site has helped me so much and I hope this helps you too (by the way PTM has for all 3 sciences and math too) just simply type the lesson name along with past paper and click on the first link and you'll get yourself your answers!!!! hopefully this helps!:))

6 0
3 years ago
A proton is ejected from the sun at a speed of 2 x 10^6 m/s. How long does it take for this proton to reach earth? Answer in hou
wolverine [178]
The distance from the Sun to the Earth is 149,600,000 km.

d=149 600 000 \ km = 149 600 000 000 \ m = 1496 \cdot 10^8 \ m \\
v=2 \cdot 10^6 \ \frac{m}{s} \\ \\ \\
t=\frac{d}{v} \\ \\
t=\frac{1496 \cdot 10^8 \ m}{2 \cdot 10^6 \ \frac{m}{s}}=748 \cdot 10^2 \ s =\frac{748 \cdot 10^2 }{36 \cdot 10^2} \ h \approx \underline{\underline{20,78 \ h}}
5 0
3 years ago
What force cause the rod to become charged
gtnhenbr [62]

Answer:

electricity

If a rod is charged it is because of the electrical force acting on it

6 0
3 years ago
What is the most likely elevation of point B?<br>a. 150 ft<br>b. 200 ft<br>c. 125 ft<br>d. 225 ft​
zepelin [54]

Answer:

D

Explanation:

erm i think its 225 ft?

7 0
4 years ago
Read 2 more answers
The Ha line of the Balmer series is emitted in the transition from n-3 to n 2. Compute the wavelength of this line for H and 2H.
Citrus2011 [14]

Explanation:

According to Rydberg's formula, the wavelength of the balmer series is given by:

\frac{1}{\lambda}=R(\frac{1}{2^2}-\frac{1}{3^2})

R is Rydberg constant for an especific hydrogen-like atom, we may calculate R for hydrogen and deuterium atoms from:

R=\frac{R_{\infty}}{(1+\frac{m_e}{M})}

Here, R_{\infty} is the "general" Rydberg constant, m_e is electron's mass and M is the mass of the atom nucleus

For hydrogen, we have, M=1.67*10^{-27}kg:

R_H=\frac{1.09737*10^7m^{-1}}{(1+\frac{9.11*10^{-31}kg}{1.67*10^{-27}kg})}\\R_H=1.09677*10^7m^{-1}

Now, we calculate the wavelength for hydrogen:

\frac{1}{\lambda}=R_H(\frac{1}{2^2}-\frac{1}{3^2})\\\lambda=[R_H(\frac{1}{2^2}-\frac{1}{3^2})]^{-1}\\\lambda=[1.0967*10^7m^{-1}(\frac{1}{2^2}-\frac{1}{3^2})]^{-1}\\\lambda=6.5646*10^{-7}m=656.46nm

For deuterium, we have M=2(1.67*10^{-27}kg):

R_D=\frac{1.09737*10^7m^{-1}}{(1+\frac{9.11*10^{-31}kg}{2*1.67*10^{-27}kg})}\\R_D=1.09707*10^7m^{-1}\\\\\lambda=[R_D(\frac{1}{2^2}-\frac{1}{3^2})]^{-1}\\\lambda=[1.09707*10^7m^{-1}(\frac{1}{2^2}-\frac{1}{3^2})]^{-1}\\\lambda=6.5629*10^{-7}=656.29nm

5 0
3 years ago
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