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Tatiana [17]
3 years ago
10

The upper part of the mantle and the crust are called the__________

Physics
2 answers:
swat323 years ago
7 0

Answer: Lithosphere

Explanation:

nikitadnepr [17]3 years ago
3 0

Answer:

lithosphere is the upper part of the mantle and the crust

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A boy throws a ball into the air at 10.2 m/s. Assuming that only gravity acts on the ball, how high does it rise, in m?
ozzi
Answer: 5.31 meters

Explanation: Use conservation of energy. Initial energy equals final energy. Initially, there is only kinetic energy (because height = 0 initially). At the end, kinetic energy equals 0 because at max height, there is max potential energy and the ball stops moving for a split second.

mgh = .5mv^2
Masses cancel out
gh = .5v^2
(9.8)(h) = .5(10.2^2)
Solve for h. h = 5.31 meters
5 0
3 years ago
A student performing a double-slit experiment is using a green laser with a wavelength of 550 nm. She is confused when the m = 5
sweet [91]

Answer:

d = 52 μm

Explanation:

given,

wavelength of the light source (λ)= 550 nm

distance to form interference pattern(D) = 1.5 m

y = 1.6 cm = 0.016 m

width of the slits = ?

now, using displacement formula

 y = \dfrac{m\lambda\ D}{d}

for the first maxima, m = 1

 d = \dfrac{1\times \lambda\ D}{y}

 d = \dfrac{1\times  550 \times 10^{-9}\times 1.5}{0.016}

       d = 5.2 x 10⁻⁶ m

       d = 52 μm

hence, the width of her slits is equal to d = 52 μm

3 0
3 years ago
What is the speed of a wave on a string with a wavelength of 1.75 m and a frequency of 2.0 Hz
deff fn [24]

Answer:

V=3.5 m/s

Explanation:

V=(F)(W)

V=(2)(1.75)

V= 3.5 m/s

7 0
2 years ago
A manometer is used to measure the air pressure in a tank. the fluid used has a specific gravity of 1.25, and the differential h
BartSMP [9]
Specific Gravity of the fluid = 1.25 
Height h = 28 in
 Atmospheric Pressure = 12.7 psia
 Density of water = 62.4 lbm/ft^3 at 32F
 Density of the Fluid = Specific Gravity of the fluid x Density of water = 1.25 x 62.4
 Density of the Fluid p = 78 lbm/ft^3
 Difference in pressure as we got the differential height, dP = p x g x h  dP = (78 lbm/ft^3) x (32.174 ft/s^2) x (28/12 ft) [ 1 lbf / 32.174 ft/s^2] [1 ft^2 /
144in^2]
 Difference in pressure = 1.26 psia
 (a) Pressure in the arm that is at Higher 
 P = Atmospheric Pressure - Pressure difference = 12.7 - 1.26 = 11.44 psia
 (b) Pressure in the tank that is at Lower
 P = Atmospheric Pressure + Pressure difference = 12.7 + 1.26 = 13.96psia
4 0
3 years ago
Plz do all of it i will give brainlest and thanks to best answer<br> plz do it right
Gelneren [198K]

Answer:

d

Explanation:

8 0
3 years ago
Read 2 more answers
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