Given
Three 7 ohm resistor are in series.
The battery is V=10V
To find
The equivalent resistance
Explanation
When the resistance are in series then the resistance are added to find its equivalent.
Thus the equivalent resistance is:

Conclusion
The equivalent resistance is 21 ohm
The water creates less friction between your foot and the ground
The representation of this problem is shown in Figure 1. So our goal is to find the vector

. From the figure we know that:

From geometry, we know that:

Then using
vector decomposition into components:

Therefore:

So if you want to find out <span>
how far are you from your starting point you need to know the magnitude of the vector

, that is:
</span>

Finally, let's find the <span>
compass direction of a line connecting your starting point to your final position. What we are looking for here is an angle that is shown in Figure 2 which is an angle defined with respect to the positive x-axis. Therefore:
</span>
1 atm corresponds to 760 mmHg, so we can set up a simple proportion to find how many atmospheres correspond to 570 mmHg:

and from this, we find
Color property of light would provide evidence for the idea that light is a wave
<h3><u>
Explanation:</u></h3>
The reality is that light manifests practices that are representative of both waves and particles. Young proposed that light of varying colors was formed of waves possessing various lengths, a basic theory that is popularly believed today. In contradiction, the particle theory advocates envisioned that several colors were obtained from particles holding either various masses or moving at various speeds.
All waves are perceived to experience refraction when they transpire from one means to another means. Light, similar to any wave, is apprehended to refract as it transfers from one medium into another medium.