Jasmine need to correct the error by switching the headings on the columns adding the title parallel circuits.
<h3>What is a parallel circuit?</h3>
A parallel circuit is a circuit in which the components are connected to a common junction. This implies that if one bulb goes out in a parallel connection, all the bulbs will go out.
As such, Jasmine need to correct the error by switching the headings on the columns adding the title parallel circuits.
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Answer:
The work function ϕ of the metal = 53.4196 x 10⁻¹⁶ J
Explanation:
When light is incident on a photoelectric material like metal, photoelectrons are emitted from the surface of the metal. This process is called photoelectric effect.
The relationship between the maximum kinetic energy (
) of the photoelectrons to the frequency of the absorbed photons (f) and the threshold frequency (f₀) of the photoemissive metal surface is:
= h(f − f₀)
= hf - hf₀
E is the energy of the absorbed photons: E = hf
ϕ is the work function of the surface: ϕ = hf₀
= E - ϕ
Frequency f = 8.12×10¹⁸ Hz
Maximum kinetic energy
= 4.16×10⁻¹⁷ J
Speed of light c = 3 x 10⁸ m/s
Planck's constant h = 6.63 × 10⁻³⁴ Js
E = hf = 6.63 × 10⁻³⁴ x 8.12×10¹⁸
E = 53.8356 x 10⁻¹⁶ J
from
= E - ϕ ;
ϕ = E - 
ϕ = 53.8356 x 10⁻¹⁶ - 4.16×10⁻¹⁷
ϕ = 53.4196 x 10⁻¹⁶ J
The work function of the metal ϕ = 53.4196 x 10⁻¹⁶ J
The average current density is 7.6 × 10⁵ A/m².
To calculate the current density current will be 2.4 A.
Diameter of a wire = 2mm.
The cross-sectional area of the wire is given by r = d/2
where r is the radius of the wire.
Then, the cross-sectional area is = 0.00000314159265
= 3.1 × 10⁻⁶ m².
<h3>
What is average current density?</h3>
Consider a current carrying conductor, the current density depends upon the current flow in the conductor. If the current flow in the conductor will be high then the current density will also be high. Using the average current flowing through the conductor, the average current density will be found.
Average current density j = I / A Ampere/ meter².
By substituting the values in the formula,
j = 2.4 / ( 3.1 × 10⁻⁶)
= 7.6 × 10⁵ A/m².
Hence, the current density can be calculated.
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Answer:
The total normal force acting on the system is approximately 58.8 N
Explanation:
The masses arranged in the stack are;
3 kg, 2 kg, and 1 kg
The mass of the stack system, m = 3 kg + 2 kg + 1 kg = 6 kg
Weight = The force of gravity on an object = m·g
Where;
m = The mass of the object
g = The acceleration due to gravity ≈ 9.8 m/s²
∴ The weight of the stack system, W ≈ 6 kg × 9.8 m/s² ≈ 58.8 N
The direction of the weight force = Perpendicular to the surface (acting downwards)
From Newton's third law of motion, the normal force acts perpendicular to the plane and it is equal in magnitude to the force acting perpendicular to the plane
∴ The magnitude of the total normal force acting on the system = The magnitude of the weight of the system ≈ 58.8 N
The (magnitude of the) total normal force acting on the system ≈ 58.8 N
Answer:
Equivalent resistance: 13.589 Ω
Explanation:
R series = R1 + R2 + R3 ...

Find the equivalent resistance of the right branch of the circuit:

