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swat32
3 years ago
14

The food calorie, equal to 4186 J, is a measure of how much energy is released when food is metabolized by the body. A certain b

rand of fruit-and-cereal bar contains 160 food calories per bar.
Part A
If a 67.0 kg hiker eats one of these bars, how high a mountain must he climb to "work off" the calories, assuming that all the food energy goes only into increasing gravitational potential energy?
Express your answer in meters.
Part B
If, as is typical, only 20.0 % of the food calories go into mechanical energy, what would be the answer to Part A? (Note: In this and all other problems, we are assuming that 100% of the food calories that are eaten are absorbed and used by the body. This is actually not true. A person's "metabolic efficiency" is the percentage of calories eaten that are actually used; the rest are eliminated by the body. Metabolic efficiency varies considerably from person to person.)
Express your answer in meters.
Physics
1 answer:
d1i1m1o1n [39]3 years ago
5 0
It’s definitely gonna be A
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What is the ball's acceleration?
muminat

Answer:

g, downward

Explanation:

It is given that, a baseball is thrown straight upward. The force acting on the stone is force of gravity. It is moving under the action of gravity. We know that the force of gravity always acts in a downward direction.

At the highest point, the velocity of the stone will be equal to 0. It will move will constant acceleration equal to g and it always acts in downward direction.

Hence, the correct option is (e) "downward direction".

5 0
3 years ago
An infinite long straight wire is uniformly charged, the charge density is a. Use Coulomb's law to calculate the electric field
bixtya [17]

Answer:

\vec{E} = \frac{a}{2\pi \epsilon_0 R}\^R

Explanation:

Since the wire is infinitely long, we will use Gauss' Law:

\int\vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}

We will draw an imaginary cylindrical surface with height h around the wire. The electric flux through the imaginary surface will be equal to the net charge inside the surface.

In that case, the net charge inside the imaginary surface will be the portion of wire with height h. Then the charge of that portion will be equal to

Q_{enc} = ah

The left-hand side of the Gauss' Law is the flux through the imaginary surface. Since we choose our surface as a cylinder, of which we know the area, we do not have to take the surface integral.

\int\vec{E}d\vec{a} = E2\pi R h

where R is the radius of the imaginary cylinder.

Finally, Gauss' Law gives

E2\pi Rh = \frac{ah}{\epsilon_0}\\E = \frac{a}{2\pi \epsilon_0 R}

The vector expression is

\vec{E} = \frac{a}{2\pi \epsilon_0 R}\^R

As you can see, the electric field is independent from the height h, since that is merely an imaginary cylinder to apply Gauss' Law. In the end, what matters is the charge density of the wire and the distance from the wire.

4 0
4 years ago
An object is moving north with an initial velocity of 14 m/s accelerates 5m/s for 20 seconds. What is the final velocity of the
olga2289 [7]

Use the kinematic equation: Vf=Vi+at

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Vi=14 m/s

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Vf=14+(5*20)

Vf=114 m/s.

6 0
4 years ago
Two stones, one with twice the mass of the other, are thrown straight up and rise to the same height h. Compare their changes in
Lady bird [3.3K]
<h2>The gravitational potential energy is double for stone with twice the mass of other stone.</h2>

Explanation:

Let mass of stone 1 be m.

Mass of stone 2 is twice the mass of stone 1.

Mass of stone 2 = 2m

We know that

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  PE = mgh

For stone 1 ,

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For stone 2 ,

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So the gravitational potential energy is double for stone with twice the mass of other stone.

               

4 0
3 years ago
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