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Anuta_ua [19.1K]
3 years ago
13

A baseball sits motionless near first base on a baseball diamond. What statement best explains why the baseball remains motionle

ss?
Physics
1 answer:
oksano4ka [1.4K]3 years ago
3 0

Answer:

Because no one is using that ball, so it is motionless

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Steam enters an adiabatic turbine at 10 MPa and 500oC and leaves at 10 kPa with a quality of 50.027 percent. Neglecting the chan
Blizzard [7]

Answer:

power output = 30730.71 kJ/s

Explanation:

given data

pressure  p1 = 10 MPa

temperature = 500° C

pressure p2 = 10 kPa

quality = 50.027 % = 0.50027

mass flow rate m = 15.469

to find out

power output in MW

solution

we know energy balance equation here that is

Energy (in) = Energy (out)

mh1 = P(out) + mh2  

P(out) = - m ( h2 - h1)  .................1

we know here h1 from steam table that is

h1 = 3375.1 kJ/kg and

hf = 191.81 and hfg = 2392.1 kJ/kg

h2 = hf + quality hfg

h2 = 191.81 + 0.50027 (2392.1) = 1388.50 kJ/kg

so from equation 1 we get power output

P(out) = - m ( h2 - h1)

P(out) = - 15.469 ( 1388.50 - 3375.1 )

power output = 30730.71 kJ/s

3 0
3 years ago
Where can I download high school textbooks online?​
MArishka [77]

probrably at the schools website but i dont know what school you go to so i would need more info

6 0
3 years ago
A 3.15-kg object is moving in a plane, with its x and y coordinates given by x = 6t2 − 4 and y = 5t3 + 6, where x and y are in m
ArbitrLikvidat [17]

Answer:

<h2>206.67N</h2>

Explanation:

The sum of force along both components x and y is expressed as;

\sum Fx = ma_x  \ and \ \sum Fy = ma_y

The magnitude of the net force which is also known as the resultant will be expressed as R =\sqrt{(\sum Fx)^2 + (\sum Fx )^2}

To get the resultant, we need to get the sum of the forces along each components. But first lets get the acceleration along the components first.

Given the position of the object along the x-component to be x = 6t² − 4;

a_x = \frac{d^2 x }{dt^2}

a_x = \frac{d}{dt}(\frac{dx}{dt} )\\ \\a_x = \frac{d}{dt}(6t^{2}-4  )\\\\a_x = \frac{d}{dt}(12t  )\\\\a_x = 12m/s^{2}

Similarly,

a_y = \frac{d}{dt}(\frac{dy}{dt} )\\ \\a_y = \frac{d}{dt}(5t^{3} +6 )\\\\a_y = \frac{d}{dt}(15t^{2}   )\\\\a_y = 30t\\a_y \ at \ t= 2.15s; a_y = 30(2.15)\\a_y = 64.5m/s^2

\sum F_x = 3.15 * 12 = 37.8N\\\sum F_y = 3.15 * 64.5 = 203.18N

R = \sqrt{37.8^2+203.18^2}\\ \\R = \sqrt{1428.84+41,282.11}\\ \\R = \sqrt{42.710.95}\\ \\R = 206.67N

Hence, the magnitude of the net force acting on this object at t = 2.15 s is approximately 206.67N

7 0
3 years ago
A crane lifts an air conditioner to the top of a building. If the building is 12 m high, and the air conditioner has a mass of 2
Pepsi [2]

Work needed = 23,520 J

<h3> Further explanation </h3>

Given

height = 12 m

mass = 200 kg

Required

work needed by the crane

Solution

Work is the transfer of energy caused by the force acting on a moving object  

Work is the product of force with the displacement of objects.  

Can be formulated  

W = F x d  

W = Work, J, Nm  

F = Force, N  

d = distance, m  

F = m x g

Input the value :

W = mgd

W = 200 kg x 9.8 m/s²x12 m

W = 23520 J

8 0
3 years ago
What information should be posted on or near a dishwasher?
Murljashka [212]
A.. in case of any problems that may occur you would know what company to call
7 0
3 years ago
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