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ra1l [238]
2 years ago
6

A large air-filled 0.221-kg plastic ball is thrown up into the air with an initial speed of 11.9 m/s. At a height of 2.77 m, the

ball's speed is 2.85 m/s. What fraction of its original energy has been lost to air friction?
Physics
1 answer:
kap26 [50]2 years ago
5 0

Answer:

Initial energy = (M/2)*Vo^2 = 12.80 J

Total energy at 4.7 m and V = 5 m/s:

= (M/2)*5^2 + M*g*4.7 = 1.25 + 4.61 J

Fraction of ball's energy LOST = (12.80-5.86)/12.80

= 0.542

Explanation:

I know it's not the real answer, but this will help you find the real one

Hope this helps!!!

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One complete expression of a waveform beginning at a certain point, progressing through the zero line to the wave’s highest (cre
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Answer:

wavelength.

Explanation:

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n a downhill ski race, surprisingly, little advantage is gained by getting a running start. (This is because the initial kinetic
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Total kinetic energy at the base = 343 m  + 0 = 343 m .

b )

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7 0
3 years ago
Three equal point charges, each with charge 1.05 μCμC , are placed at the vertices of an equilateral triangle whose sides are of
kirza4 [7]

Answer:

The value is U  = 0.06 \  J

Explanation:

From the question we are told that

The value of charge on each three point charge is

q_1 = q_2 = q_3 =q=  1.05 \mu C  =  1.05 *10^{-6} \  C

The length of the sides of the equilateral triangle is r  =  0.500 \

Generally the total potential energy is mathematically represented as

U  = k *  [ \frac{q_1 *  q_2}{r}  +  \frac{q_2 *  q_3}{r}   + \frac{q_3 *  q_1}{r} ]

=> U  = k * 3 * \frac{q^2}{r}

Here k is coulomb constant with value k = 9*10^{9}\  kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.

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U  = 0.06 \  J

6 0
3 years ago
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