A large air-filled 0.221-kg plastic ball is thrown up into the air with an initial speed of 11.9 m/s. At a height of 2.77 m, the
ball's speed is 2.85 m/s. What fraction of its original energy has been lost to air friction?
1 answer:
Answer:
Initial energy = (M/2)*Vo^2 = 12.80 J
Total energy at 4.7 m and V = 5 m/s:
= (M/2)*5^2 + M*g*4.7 = 1.25 + 4.61 J
Fraction of ball's energy LOST = (12.80-5.86)/12.80
= 0.542
Explanation:
I know it's not the real answer, but this will help you find the real one
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