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4 years ago

15

Will give brainliest to best answer.

1 answer:

sp2606 [1]4 years ago

3 0

D. Solar because it doesn’t release any gasses and all it needs is the natural sun

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e-lub [12.9K]

Answer:

B) Power is the rate at which work is done

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4 years ago

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The law prohibits a person from _________ an electric vehicle/"ev"-designated parking space.

Sladkaya [172]

Answer:

The law prohibits a person from barring access to an electric vehicle/"ev"-designated parking space.

8 0

3 years ago

Explain why wedges and screws are actually types of inclined planes.

slava [35]

<span>The screw is really just an inclined plane covered around with a tiny pole. The wedge is definitely an inclined plane, since it starts with a point, then rises getting thicker, as an inclined plane. </span>

5 0

4 years ago

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A marble is dropped off the top of a building. Find it's velocity and how far below to its dropping point for the first 10 secon

WINSTONCH [101]

1) velocity: 98 m/s downward

Explanation:

The marble moves by uniformly accelerated motion, with constant acceleration a=g=-9.8 m/s^2 directed towards the ground. Therefore, its velocity at time t is given by:

$v(t)=v_0 +at$

where

$v_0 = 0$ is the initial velocity

$a=g=-9.8 m/s^2$ is the acceleration

$t$ is the time

Substituting t = 10 s, we find:

$v(10 s)=0+(-9.8 m/s^2)(10 s)=-98 m/s$

And the negative sign means the direction of the velocity is downward.

2) Distance covered: 490 m

The distance covered in an uniformly accelerated motion can be found with the formula:

$S=\frac{1}{2}at^2$

where

$a=-9.8 m/s^2$ is the acceleration

t is the time

Substituting t=10 s, we find

$S=\frac{1}{2}at^2=\frac{1}{2}(-9.8 m/s^2)(10 s)^2=-490 m$

And the negative sign means the displacement is below the dropping point.

4 0

3 years ago

A bicycle of mass m requires 50 J of work to move from rest to a final speed v. If the same amount of work is performed during t

insens350 [35]

Answer:

The final speed of the second bicycle is (v·√2)/2

Explanation:

The mass of the given bicycle = m

The amount of work required to move the bicycle from rest to speed v = 50 J

The final speed of the first bicycle = v

The mass of the second bicycle = 2m

Therefore, from conservation of energy, we have;

Work required by the first bicycle = Kinetic energy gained by the bicycle

The kinetic energy = 1/2·m·v²

∴ Energy required by the first bicycle = 50 J = 1/2·m·v²

Given that the same amount of work is performed on the second bicycle, we have;

Work performed on the second bicycle = 50 J = kinetic energy of second bicycle = 1/2·(2·m)·v₂²

Also, given that 50 J = 1/2·m·v², we have;

Work performed on the second bicycle = 50 J = 1/2·m·v²= 1/2·(2·m)·v₂²

1/2·m·v²= 1/2·(2·m)·v₂²

m·v² = 2·m·v₂²

v² = 2·v₂²

v₂ = √(v²/2) = v/√2 = (v·√2)/2

v₂ = (v·√2)/2

The final speed of the second bicycle = v₂ = (v·√2)/2.

3 0

3 years ago