2.0y i think this is guess but if it right then thats good
Answer:
![F_{net} = 232.8 N](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20232.8%20N)
towards right so it is -15 degree
Explanation:
Net force in forward direction due to all three is given as
![F_x = F_1 + F_2cos45 + F_3cos45](https://tex.z-dn.net/?f=F_x%20%3D%20F_1%20%2B%20F_2cos45%20%2B%20F_3cos45)
here we know that
![F_1 = 77.3 N](https://tex.z-dn.net/?f=F_1%20%3D%2077.3%20N)
![F_2 = 61.7 N](https://tex.z-dn.net/?f=F_2%20%3D%2061.7%20N)
![F_3 = 147 N](https://tex.z-dn.net/?f=F_3%20%3D%20147%20N)
![F_x = 77.3 + 61.7 cos45 + 147 cos45](https://tex.z-dn.net/?f=F_x%20%3D%2077.3%20%2B%2061.7%20cos45%20%2B%20147%20cos45)
![F_x = 224.9 N](https://tex.z-dn.net/?f=F_x%20%3D%20224.9%20N)
Similarly in Y direction we will have
![F_y = F_3 sin45 - F_2 sin45](https://tex.z-dn.net/?f=F_y%20%3D%20F_3%20sin45%20-%20F_2%20sin45)
![F_y = (147 - 61.7)sin45](https://tex.z-dn.net/?f=F_y%20%3D%20%28147%20-%2061.7%29sin45)
![F_y = 60.3 N](https://tex.z-dn.net/?f=F_y%20%3D%2060.3%20N)
Now the net force on the donkey is given as
![F_{net} = \sqrt{F_x^2 + F_y^2}](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20%5Csqrt%7BF_x%5E2%20%2B%20F_y%5E2%7D)
![F_{net} = \sqrt{224.9^2 + 60.3^2}](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20%5Csqrt%7B224.9%5E2%20%2B%2060.3%5E2%7D)
![F_{net} = 232.8 N](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20232.8%20N)
Now direction of force is given as
![tan\theta = \frac{F_y}{F_x}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%20%5Cfrac%7BF_y%7D%7BF_x%7D)
![tan\theta = \frac{60.3}{224.9}](https://tex.z-dn.net/?f=tan%5Ctheta%20%3D%20%5Cfrac%7B60.3%7D%7B224.9%7D)
towards right so it is -15 degree
Answer:
the reason for the acceleration month that the coefficient of kinetic friction is less than the coefficient of satic frictionExplanation:
This exercise uses Newton's second law with the condition that the acceleration is zero, by the time the body begins to slide. At this point the balance of forces is
fr- w || = 0
The expression for friction force is that it is proportional to the coefficient of friction by normal.
fr = μ N
When the system is immobile, the coefficient of friction is called static coefficient and has a value, this is due to the union between the surface, when the movement begins some joints are broken giving rise to coefficient of kinetic friction less than static.
In consequence a lower friction force, which is why the system comes out of balance and begins to accelerate.
μ kinetic <μ static
In all this movement the normal with changed that the angle of the table remains fixed.
Consequently, the reason for the acceleration month that the coefficient of kinetic friction is less than the coefficient of satic friction
A 50kg object on earth weighs 81.67 on the moon
Satellites are objects which orbit the planet. The natural satellite of Earth, in this case, is moon