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fenix001 [56]
1 year ago
6

A sinusoidal wave of wavelength 2.00m and amplitude 0.100 m travels on a string with a speed of 1.00 m/s to the right. At t = 0

, the left end of the string is at the origin. For this wave, find.(e) the left end of the string.
Physics
1 answer:
Elanso [62]1 year ago
5 0

The left end of the string is given as y = - 0.100 sin (3.14t )

<h3>How to find the sinusoidal wave</h3>

We would have to create an equation of this form

The wave function equation

y = A sin ( π*x - ω* t )

When we put in the values that we have in the equation

y = 0.100 sin ( 3.14 x - 3.14 t )

Due to the fact that it is the left end of the string, the value that we would have for x is going to be 0, hence we would have

y = 0.100 sin (3.14 * (0) - 3.14t )

Then y would be 0.100 sin (- 3.14t )

This would give us the final equation

y = - 0.100 sin (3.14t )

Hence we would have the left end of the string as y = - 0.100 sin (3.14t )

Read more on sinusoidal wave here:

brainly.com/question/20912200

#SPJ4

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All stars in a stellar cluster have roughly the same distance.

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Open clusters have a tendency to be blue in color. They frequently include glowing gas and dust. The stars in an open cluster are young stars that all formed from the equal nebula. These warm blue stars are in an open cluster known as the Jewel Bo

<h3>Are stars in the identical cluster?</h3>

Though stellar associations are grouped in with megastar clusters, they're pretty a bit different. "Stellar associations are companies of tens to hundreds of stars that have similar a while and metallicities, and are moving in roughly the equal direction within the galaxy, but are no longer gravitationally bound," Geller said.

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<h3>brainly.com/question/20326847</h3><h3 /><h3>#SPJ4</h3>
4 0
1 year ago
Consider the following list of numbers. 129, 685, 125, 511, 601, 52, 46 The height of a binary search tree is the maximum number
NemiM [27]

Answer:

The height of the tree is three (3) deep

Explanation:

It's 3 deep

Under 129, comes 125 and 685;

Under 125, comes 52 : Under 685, comes 511;

Under 52, comes 46 : Under 511, is 601.

This is illustrated below.

129

∧

125,685

|,|

52,511

|,|

46,601

5 0
3 years ago
PLEASE HELP!!! I have so much work left to do. PLEASE!!!
Neko [114]

Answer:

the answer is C.

Explanation:

6 0
2 years ago
Which is the pathway for information through a neuron?
Mariulka [41]
Information travels along the axon once an impulse is received. The axon then takes it to the place where it can be sent off to another neuron

<span>dendrite → cell body → axon → axon terminals is the correct answer</span>

<span>If I managed to help you, please make sure to mark my answer as the "Brainliest" answer. Thanks! :)</span>
6 0
3 years ago
Read 2 more answers
A 50 Kg box sits at rest on a 30 degree ramp where the coef of static friction is 0.5773. If your push was directed at an angle
emmasim [6.3K]

<u>Given data:</u>

m= 50 Kg,

W= m×g = 50 × 9.81 = 490.5 N

ramp angle (α) = 30 degrees,

coefficient of friction (μs) = 0.5773,

Push at an angle (Θ) = 40 degrees,

Determine: Push to get box move up (P)=?

From the figure,

Resolving the forces along the plane

W sinα + μs.R = P cos Θ       --------------------- (i)

Resolving the forces perpendicular to the inclined plane

W cosα = R+Psin Θ  =>  R= W cosα - Psin Θ -------------- (ii)

Solving (i) and (ii) and keeping <em>μs = tan Φ, Φ = Θ </em>

<em>Pmin = W sin( α +Θ  )</em>

<em>          = W[ sin α.Cos Θ + cos α.sin Θ]</em>

<em>           = 490.5 [ (sin 30.cos40) + (cos30.sin 40)]</em>

<em>           = 460.9 N</em>

<em>Minimum push required to move the box up the ramp is 460.9 N</em>


7 0
3 years ago
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