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Montano1993 [528]
3 years ago
7

If three forces F1 = 20N, 300NE, F2 = 50N along W, F3 = 40N 500NW act on a body. Find the resultant in magnitude and direction.​

Physics
1 answer:
patriot [66]3 years ago
4 0

Answer:

110N north west

Explanation:

.........

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Two 18 x 21 x 25 mm rubber mounts are used to isolate the vibrational motion of a machine from its supports. A 420-N applied loa
Zolol [24]

Answer:

a)  γ =0.055556

b)  t = 0.4 MPa

Explanation:

Given:

- The dimensions of rubber block : 18 x 21 x 25

- A load was applied at upper frame P = 420 N

- The rubber deflects dx = 1 mm downwards

Find:

(a) average shear strain in the rubber mounts

(b) average shear stress in the rubber mounts.

Solution:

- For average shear strain we have the definition:

                                 γ = dx / y

Where,  

γ: The shear strain.

dx : Deflection along the shear force

y : The length perpendicular to deflection.

- From given data we have dx = 1mm, and the dimension of block perpendicular to deflection is the a dimension. Hence, dx = 0.001 and y =0.018 m:

                                  γ = 0.001 / 0.018 = 0.055556

- The average shear stress along the mating flat surface. We have from definition:

                                   t = F_shear / Area

- Where, F_shear: The shear force on each rubber block is P/2.

Hence,

                                   t = (P/2) / b*c

Plug values in:

                                   t = (420/2) / (0.021*0.025)

                                  t = 0.4 MPa

6 0
3 years ago
Compare blue and red light from the visible spectrum. which has: the longer wavelength? the greater frequency? the greater energ
Hitman42 [59]
1) By looking at the table of the visible spectrum, we see that blue light has a wavelength in the range [450-490 nm], while red light has wavelength in the range [620-750 nm]. Therefore, red light has longer wavelength than blue light.

2) The frequency f of an electromagnetic wave is related to its wavelength \lambda by the formula
f= \frac{c}{\lambda}
where c is the speed of light. We see that the frequency is inversely proportional to the wavelength, so the shorter the wavelength, the greater the frequency. In this case, blue light has shorter wavelength than red light, so blue light has greater frequency than red light.

3) The energy of the photons of an electromagnetic wave is given by
E=hf
where h is the Planck constant and f is the frequency. We see that the energy is directly proportional to the frequency, so the greater the frequency, the greater the energy. In this problem, blue light has greater frequency than red light, so blue light has also greater energy than red light.
6 0
3 years ago
The electric field strength is 1.70 × 104 N/C inside a parallel-plate capacitor with a 0.800 m spacing. An electron is released
Vesna [10]

Answer:

Here, "v" is the velocity of electron and "V" is the potential.

4 0
3 years ago
This problem, a squid at rest suddenly sees a predator coming toward it and needs to escape. Assume the following:______.
makkiz [27]

Answer:

6.79 m/s

Explanation:

By applying the principle of conservation of momentum.

The total momentum = MV - mv = 0 (since the squid is beginning at rest)

the mass of the squid (M) in absence of water in its cavity = (6.5 - 1.75) kg

= 4.75 kg

speed of the squid (V) = 2.5 m/s

mass of the water expelled (m) = 1.75 kg

speed of the water (v) = ???

∴

4.75 × 2.5 = 1.75 × v

v = \dfrac{4.75 \times 2.5}{1.75 }

v = 6.79 m/s

8 0
3 years ago
An RC circuit consists of a resistor with resistance 1.0 kΩ, a 120-V battery, and two capacitors, C1 and C2, with capacitances o
Serhud [2]

Answer:

Q_t= 8.3 * 10^3 C

Explanation:

From the question we are told that:

Resistor R=1000ohms

Voltage v=120_V

Capacitance of c_1 c_1=20 \mu F

Capacitance of c_2 c_2=60 \mu F

Time t=0

Generally the equation for charges is mathematically given by

For C_1\\Charge\ on\ C_1 = CV = 20*120 = 2400 μC = 2.4 x 10^-3 C\\Charge\ on\ C_1 = 2400 μC = 2.4 x 10^-3 C\\Charge\ on\ C_1 = 2.4 x 10^-3 C\\

ForC_2\\Charge on C_2 = 60*120 =7200 μC =  7.2 x 10^-3\\Charge on C_2 =  7.2 x 10^-3

Generally the equation for voltage across capacitors is mathematically given by

V_c(t)=V(1-e^{-t/RC})

C=C_1+C_2=80 \mu f\\t=2RC=>160000s

V_c(t)=120(1-e^{-(160000)/1000*(80)})

V_c(t)=103.7598

Generally the equation for charges is mathematically given by

Q1(t) = C1Vc(t)\\Q1(t) = 20*103.7598\\Q1(t) = 2075.196\\\\Q2(t) = 60*103.7598\\Q2(t) = 6225.6\\

Generally the equation for total charges Q_t is mathematically given by

Q_t=Q1(t)+Q2(t)

Q_t= 8.3 * 10^3 C

5 0
3 years ago
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