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prohojiy [21]
3 years ago
9

A child approaches a stop sign and applies the brakes to slow to a stop. If the bicycle and child were originally traveling at 9

.00 m/s and the breaks cause a deceleration of magnitude 1.20 m/s^2, how long will it take the child to stop?
Physics
1 answer:
user100 [1]3 years ago
6 0

Answer:

7.5secs

Explanation:

Using the equation of motion

v = u + at

v is the final velocity = 0m/s

u is the initial velocity = 9m/s

a is the deceleration = -1.2m/s²

t is the required time

Substitute;

0 = 9 + 1.2(t)

-9 = -1.2t

t = -9/-1.2

t = 7.5secs

hence it takes the child 7.5secs to stop

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 <span>let the fsh jump with initial velocity (u) in direction (angle p) with horizontal 

it can cross and reach top of trajectory if its top height h = 1.5m 
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so it will able to cross</span>
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daser333 [38]

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

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